anonymous one year ago How many liters of 0.85 M HCl solution would react completely with 3.5 moles Ca(OH)2? Ca(OH)2(s) + 2 HCl(aq) yields CaCl2(aq) + 2 H2O(l) 1.5 L HCl(aq) 8.2 L HCl(aq) 2.1 L HCl(aq) 6.0 L HCl(aq)

1. anonymous

@Nnesha

2. anonymous

@e.mccormick

3. JFraser

See the molar ratio from the balanced reaction? Telling you every time you use 1 mole of calcium hydroxide, you need $$two$$ miles of HCl to react fully with it

4. anonymous

@jfraser so c

5. JFraser

No. The problem says you start with 3.5 moles of calcium hydroxide, so how many moles of HCl will fully react with that much? (Twice as much)

6. JFraser

The balanced reaction tells us $$ratios$$, not absolute amounts

7. anonymous

@jfraser so d would be correct?

8. JFraser

You're jumping. Stop jumping. If you have to use 3.5 moles of calcium hydroxide, you must also use 7 moles of HCl. But the question is asking about the $$volume$$ of HCl solution needed. The $$concentration$$ of the HCl is 0.85mol/L

9. anonymous

oh so b @jfraser thanks

10. JFraser

Each 1L of solution contains only 0.85 moles of HCl $7mol HCl * \frac{1L HCl}{0.85mol HCl}$

11. JFraser

Ye