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anonymous
 one year ago
*(FAN AND MEDAL) HELP!!!
anonymous
 one year ago
*(FAN AND MEDAL) HELP!!!

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@pinkbubbles @ganeshie8

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I NEED THE LAST 3 PLEASE I REALLY NEED HELP GUYS

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i appreciate please help me!!!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Haseeb96 ??? please :(

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@undeadknight26 @mathmath333

undeadknight26
 one year ago
Best ResponseYou've already chosen the best response.0All of them need answered?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1question 4) hwre we have to evaluate this quantities: \[\Large f\left( {10} \right) = ...?\;f\left( 3 \right) = ...?\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1you have to use your function: \[\Large f\left( x \right) = 2 \times {3^x}\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1you have to replace x with 3 and x with 10

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0are you there @Michele_Laino ?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1hint: \[\Large \begin{gathered} f\left( 3 \right) = 2 \times {3^3} = 2 \times 27 = ...? \hfill \\ f\left( {10} \right) = 2 \times {3^{10}} = ...? \hfill \\ \end{gathered} \]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1f(10) is a very big number, so please use a calculator

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i use wolfram i copy and paste: 0?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1now we have to compute the same quantities, using this function: \[\Large g\left( x \right) = 3 \times {4^x}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0where its the formula, or its the same formula?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1namely we have to evaluate these quantities: \[\Large \begin{gathered} g\left( 2 \right) = 3 \times {4^2} = 3 \times 16 = ...? \hfill \\ g\left( {10} \right) = 3 \times {4^{10}} = ...? \hfill \\ \end{gathered} \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0g(2) = 3x4^2 = 3x16 = 48? g(10) = 3x4^10 = 0?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.148 is right! the second is a very big number g(10)=3*1048576=...?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1since 4^10=1,048,576

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what i need to do now?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1next ste: we have to write the function of Carter

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1we have to read the text of your problem

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1I think that the function used by Carter is: \[\Large h\left( x \right) = 10 \times {2^x}\] am I right?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1ok! now we have to compute these quantities: \[\Large \begin{gathered} h\left( 2 \right) = 10 \times {2^2} = 10 \times 4 = ... \hfill \\ h\left( {10} \right) = 10 \times {2^{10}} = 10 \times 1024 = ... \hfill \\ \end{gathered} \]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1sorry I have made an error, we have to compute g(3) and h(3) not g(2) and h(2)

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1\[\Large \begin{gathered} g\left( 3 \right) = 3 \times {4^3} = 3 \times 64 = ...? \hfill \\ g\left( {10} \right) = 3 \times {4^{10}} = ...? \hfill \\ \end{gathered} \] \[\Large \begin{gathered} h\left( 3 \right) = 10 \times {2^3} = 10 \times 8 = ... \hfill \\ h\left( {10} \right) = 10 \times {2^{10}} = 10 \times 1024 = ... \hfill \\ \end{gathered} \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0h(2)=10x2^2=10x4= 40? h(10)=10x2^10x1024= 10485760?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im not sure about the last one, but im right?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1we have: \[\Large \begin{gathered} h\left( 3 \right) = 10 \times {2^3} = 10 \times 8 = 80 \hfill \\ h\left( {10} \right) = 10 \times {2^{10}} = 10 \times 1024 = 10240 \hfill \\ \end{gathered} \]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1so, we have completed the question 4)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yea, but whats nexts? i did something wrong?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1I think you have done right!

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1now we have to compare the graph of the new function of Amber, with the graph of the old function of the same Amber

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1the new function is: \[\Large {g_2}\left( x \right) = 3 \times {4^x} + 45\] whereas the old function is: \[\Large {g_1}\left( x \right) = 3 \times {4^x}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i need to solve that? right?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1I think that we have to draw both those graphs

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im not good doing graph ;(

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1it is simple, the graph of the old function is like below: dw:1437499913652:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i need to graph now the new function?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1the new graph is shifted up by 45 units with respect to the old one, like this: dw:1437500095683:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you already did the graph

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1yes! as you can see it is simple

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yea i see, so we done with number 4?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1we have done with number 5)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wait wait i dont see the answer for # 4 :(

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1the answer of #4 are given by the subsequent quantites: f(3), f(10) g(3), g(10) h(3), h(10)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok, so the asnwer for # 5 are the graphs? right

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so we can move to # 6?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can you continue? ^_^

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1for question #6 you have to compare the quantities above, namely f(3), f(10) g(3), g(10) h(3), h(10)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how? like that: f(3)(10) g(3)(10) h(3)(10)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0idk how to compare the quantities

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1we have to compare these values: \[\begin{gathered} f\left( 3 \right) = 2 \times {3^3} = 2 \times 27 = 54 \hfill \\ f\left( {10} \right) = 2 \times {3^{10}} = 118098 \hfill \\ \end{gathered} \] \[\begin{gathered} g\left( 3 \right) = 3 \times {4^3} = 3 \times 64 = 192 \hfill \\ g\left( {10} \right) = 3 \times {4^{10}} = 3145728 \hfill \\ \end{gathered} \] \[\begin{gathered} h\left( 3 \right) = 10 \times {2^3} = 10 \times 8 = 80 \hfill \\ h\left( {10} \right) = 10 \times {2^{10}} = 10 \times 1024 = 10240 \hfill \\ \end{gathered} \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes ik, but my question its how because if im right, i see you already did, right?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1we have to establish which student increased fastly the number of shared posts

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1from those numbers above, can you see the requested student

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1please, look at the posts shared by Amber, her function is g(x)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0g(3)=3×43=3×64=192 g(10)=3×410=3145728

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1within the same time, namely 1 week her shared posts went from 192, to more than 3 millions, right?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1whereas the other two students have not been so fast, right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0f(3), f(10) h(3), h(10)?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1so, who is the fastest student in sharing the posts?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1yes! better if we answer saying that the fastest student is Amber

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so the answer for # 6 its: the fastest student is Amber

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1yes! Please wait Look at these formulas: dw:1437502126622:dw

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1we have three powers. Now i ask you, which power has the highest base?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1are you sure? we have: 2 < 3 < 4

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no wait let me see again

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1yes! that's right! That is why Amber was the fastest student in sharing her posts

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1we have answered to question #6

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok, for make sure the answer for # 6 its:

anonymous
 one year ago
Best ResponseYou've already chosen the best response.06) g(x) = 3.4^x the fastest student is Amber?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1yes! you are correct here is my answer equivalent to yours: the fastest student is Amber we can recognize that fact, since in the Amber's function, appears a power with the highest base

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thank you so much!!!! can we now move to the last one?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1the question #7 is equivalent to question #6, since the answer is the same, namely I prefer to choose Amber, since she is very fast in sharing her posts

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so the answer for #7 its the same answer of #6?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but i want to write in others words

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1my answer is: "I prefer share my posts in the same manner of Amber, since she has more shares, so she is very fast in sharing her posts"

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thank you so much, you help me a lot, you're awesome!!!!! ^_^
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