A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • one year ago

*(FAN AND MEDAL) HELP!!!

  • This Question is Closed
  1. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @pinkbubbles @ganeshie8

  2. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I NEED THE LAST 3 PLEASE I REALLY NEED HELP GUYS

    1 Attachment
  3. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i appreciate please help me!!!

  4. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @Vocaloid

  5. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @Haseeb96 ??? please :(

  6. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @campbell_st

  7. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @dan815

  8. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @Michele_Laino

  9. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @undeadknight26 @mathmath333

  10. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    help :(

  11. undeadknight26
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    All of them need answered?

  12. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    question 4) hwre we have to evaluate this quantities: \[\Large f\left( {10} \right) = ...?\;f\left( 3 \right) = ...?\]

  13. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    oops..these*

  14. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    (10)(3)

  15. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ?

  16. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    30?

  17. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    you have to use your function: \[\Large f\left( x \right) = 2 \times {3^x}\]

  18. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok, wait

  19. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    idk ;/

  20. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    you have to replace x with 3 and x with 10

  21. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oh

  22. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    f (3) = 2 x 3^10

  23. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @Michele_Laino

  24. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    are you there @Michele_Laino ?

  25. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @Michele_Laino

  26. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    hint: \[\Large \begin{gathered} f\left( 3 \right) = 2 \times {3^3} = 2 \times 27 = ...? \hfill \\ f\left( {10} \right) = 2 \times {3^{10}} = ...? \hfill \\ \end{gathered} \]

  27. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    wait

  28. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    f(10) is a very big number, so please use a calculator

  29. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i use wolfram i copy and paste: 0?

  30. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yes!

  31. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so whats nexts?

  32. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    now we have to compute the same quantities, using this function: \[\Large g\left( x \right) = 3 \times {4^x}\]

  33. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    where its the formula, or its the same formula?

  34. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    namely we have to evaluate these quantities: \[\Large \begin{gathered} g\left( 2 \right) = 3 \times {4^2} = 3 \times 16 = ...? \hfill \\ g\left( {10} \right) = 3 \times {4^{10}} = ...? \hfill \\ \end{gathered} \]

  35. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    g(2) = 3x4^2 = 3x16 = 48? g(10) = 3x4^10 = 0?

  36. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    im right?

  37. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    48 is right! the second is a very big number g(10)=3*1048576=...?

  38. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    since 4^10=1,048,576

  39. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    what i need to do now?

  40. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    next ste: we have to write the function of Carter

  41. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    how?

  42. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    we have to read the text of your problem

  43. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    I think that the function used by Carter is: \[\Large h\left( x \right) = 10 \times {2^x}\] am I right?

  44. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes i think so

  45. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    ok! now we have to compute these quantities: \[\Large \begin{gathered} h\left( 2 \right) = 10 \times {2^2} = 10 \times 4 = ... \hfill \\ h\left( {10} \right) = 10 \times {2^{10}} = 10 \times 1024 = ... \hfill \\ \end{gathered} \]

  46. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    carter: 10(2)^x?

  47. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok

  48. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    sorry I have made an error, we have to compute g(3) and h(3) not g(2) and h(2)

  49. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    \[\Large \begin{gathered} g\left( 3 \right) = 3 \times {4^3} = 3 \times 64 = ...? \hfill \\ g\left( {10} \right) = 3 \times {4^{10}} = ...? \hfill \\ \end{gathered} \] \[\Large \begin{gathered} h\left( 3 \right) = 10 \times {2^3} = 10 \times 8 = ... \hfill \\ h\left( {10} \right) = 10 \times {2^{10}} = 10 \times 1024 = ... \hfill \\ \end{gathered} \]

  50. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    h(2)=10x2^2=10x4= 40? h(10)=10x2^10x1024= 10485760?

  51. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    im not sure about the last one, but im right?

  52. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    we have: \[\Large \begin{gathered} h\left( 3 \right) = 10 \times {2^3} = 10 \times 8 = 80 \hfill \\ h\left( {10} \right) = 10 \times {2^{10}} = 10 \times 1024 = 10240 \hfill \\ \end{gathered} \]

  53. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so...

  54. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    so, we have completed the question 4)

  55. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yea, but whats nexts? i did something wrong?

  56. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    I think you have done right!

  57. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    now we have to compare the graph of the new function of Amber, with the graph of the old function of the same Amber

  58. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    the new function is: \[\Large {g_2}\left( x \right) = 3 \times {4^x} + 45\] whereas the old function is: \[\Large {g_1}\left( x \right) = 3 \times {4^x}\]

  59. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i need to solve that? right?

  60. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    I think that we have to draw both those graphs

  61. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    im not good doing graph ;(

  62. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    it is simple, the graph of the old function is like below: |dw:1437499913652:dw|

  63. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i need to graph now the new function?

  64. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yes!

  65. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    the new graph is shifted up by 45 units with respect to the old one, like this: |dw:1437500095683:dw|

  66. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    you already did the graph

  67. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yes! as you can see it is simple

  68. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yea i see, so we done with number 4?

  69. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    we have done with number 5)

  70. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    wait wait i dont see the answer for # 4 :(

  71. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    the answer of #4 are given by the subsequent quantites: f(3), f(10) g(3), g(10) h(3), h(10)

  72. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok, so the asnwer for # 5 are the graphs? right

  73. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yes! right!

  74. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so we can move to # 6?

  75. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yes!

  76. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    can you continue? ^_^

  77. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    ok!

  78. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    for question #6 you have to compare the quantities above, namely f(3), f(10) g(3), g(10) h(3), h(10)

  79. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    how? like that: f(3)(10) g(3)(10) h(3)(10)

  80. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    their values

  81. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    idk how to compare the quantities

  82. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    we have to compare these values: \[\begin{gathered} f\left( 3 \right) = 2 \times {3^3} = 2 \times 27 = 54 \hfill \\ f\left( {10} \right) = 2 \times {3^{10}} = 118098 \hfill \\ \end{gathered} \] \[\begin{gathered} g\left( 3 \right) = 3 \times {4^3} = 3 \times 64 = 192 \hfill \\ g\left( {10} \right) = 3 \times {4^{10}} = 3145728 \hfill \\ \end{gathered} \] \[\begin{gathered} h\left( 3 \right) = 10 \times {2^3} = 10 \times 8 = 80 \hfill \\ h\left( {10} \right) = 10 \times {2^{10}} = 10 \times 1024 = 10240 \hfill \\ \end{gathered} \]

  83. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes ik, but my question its how because if im right, i see you already did, right?

  84. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    we have to establish which student increased fastly the number of shared posts

  85. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oh

  86. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    from those numbers above, can you see the requested student

  87. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    please, look at the posts shared by Amber, her function is g(x)

  88. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    g(3)=3×43=3×64=192 g(10)=3×410=3145728

  89. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ?

  90. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    g(3), g(10)

  91. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    within the same time, namely 1 week her shared posts went from 192, to more than 3 millions, right?

  92. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes

  93. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    whereas the other two students have not been so fast, right?

  94. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    f(3), f(10) h(3), h(10)?

  95. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes

  96. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    so, who is the fastest student in sharing the posts?

  97. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    g(10)? right?

  98. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yes! better if we answer saying that the fastest student is Amber

  99. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so the answer for # 6 its: the fastest student is Amber

  100. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    right?

  101. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yes! Please wait Look at these formulas: |dw:1437502126622:dw|

  102. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    we have three powers. Now i ask you, which power has the highest base?

  103. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    f(x)?

  104. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    are you sure? we have: 2 < 3 < 4

  105. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    no wait let me see again

  106. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so, its, g(x)? :/

  107. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yes! that's right! That is why Amber was the fastest student in sharing her posts

  108. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    we have answered to question #6

  109. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok, for make sure the answer for # 6 its:

  110. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    6) g(x) = 3.4^x the fastest student is Amber?

  111. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i write good?

  112. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yes! you are correct here is my answer equivalent to yours: the fastest student is Amber we can recognize that fact, since in the Amber's function, appears a power with the highest base

  113. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thank you so much!!!! can we now move to the last one?

  114. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yes! sure! :)

  115. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    the question #7 is equivalent to question #6, since the answer is the same, namely I prefer to choose Amber, since she is very fast in sharing her posts

  116. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so the answer for #7 its the same answer of #6?

  117. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yes!

  118. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    really? omg

  119. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yes! really!

  120. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    but i want to write in others words

  121. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    my answer is: "I prefer share my posts in the same manner of Amber, since she has more shares, so she is very fast in sharing her posts"

  122. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thank you so much, you help me a lot, you're awesome!!!!! ^_^

  123. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    :)

  124. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.