anonymous one year ago Solve for x: |x + 2| + 16 = 14 A. x = −32 and x = −4 B. x = −4 and x = 0 C. x = 0 and x = 28 D. No solution

1. anonymous

@HectorH

2. anonymous

i think its D

3. Janu16

No solution

4. anonymous

ok i was right thnx :)

5. anonymous

We subtract 16 from both sides to get $\left| x+2 \right| = -2$ Then thats impossible since absolute value bars keep it from going negative.

6. anonymous

yup :) thnx

7. Janu16

@jkl5149 its no solution

8. anonymous

@Janu16 Yes.