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help_people

  • one year ago

Given the following functions f(x) and g(x), solve for (f ⋅ g)(2) and select the correct answer below: f(x) = 3x2 + 2 g(x) = x − 8 −42 −84 42 84

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  1. help_people
    • one year ago
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    @Vocaloid @DaBest21

  2. anonymous
    • one year ago
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    im here

  3. anonymous
    • one year ago
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    first plug 2 in for x in g(x) so do 2-8

  4. anonymous
    • one year ago
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    What do u get @help_people

  5. help_people
    • one year ago
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    -6

  6. anonymous
    • one year ago
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    yep

  7. anonymous
    • one year ago
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    in 3x2 is the 2 an exponent

  8. help_people
    • one year ago
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    yes

  9. anonymous
    • one year ago
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    ok in the future just do 3x^2

  10. help_people
    • one year ago
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    ok srry

  11. anonymous
    • one year ago
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    sokay

  12. anonymous
    • one year ago
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    now do 3*2^2+2

  13. anonymous
    • one year ago
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    what do u get

  14. anonymous
    • one year ago
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    remeber do 2^2 first

  15. help_people
    • one year ago
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    14

  16. anonymous
    • one year ago
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    yep so now do 14*-6 what do u get

  17. help_people
    • one year ago
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    -84

  18. anonymous
    • one year ago
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    yep thats ur answer

  19. anonymous
    • one year ago
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    Don't forget to medal and fan if you already haven't. Plus send me a message if you need more help @help_people im actually gonna take a break

  20. help_people
    • one year ago
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    wait could you help me w. one more please please please?

  21. help_people
    • one year ago
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    please ?

  22. help_people
    • one year ago
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    i will post it here so it does not take long

  23. anonymous
    • one year ago
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    k

  24. help_people
    • one year ago
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    Given the functions k(x) = 5x − 8 and p(x) = x − 4, solve k[p(x)] and select the correct answer below. k[p(x)] = 5x − 12 k[p(x)] = 5x − 28 k[p(x)] = 5x2 − 12 k[p(x)] = 5x2 − 28

  25. help_people
    • one year ago
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    the 2s in the last 2 answer choices are exponents

  26. anonymous
    • one year ago
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    well do (x-4)*5-8 5x-20-8 5x-12

  27. anonymous
    • one year ago
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    there u go

  28. anonymous
    • one year ago
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    i gotta take a break

  29. help_people
    • one year ago
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    thank you so much have fun you deserve it :)

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