How many electrons in an atom can share the quantum numbers n= 2, l = 1, and m subscript l = -1? (2 points)
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Hey for that question how many electrons in an atom can share the quantum numbers n =2, l = 1, and mL = -1.
few things you should know:
n = the principle quantum number = the energy level your orbital is at.
l = the shape of your orbital.
mL = the orientation of those orbitals. mL can be between -l and positive l.
every orbital can hold a maximum of 2 electrons.
the first thing is that an s orbital only has one configuration l = 0 so m of l could be only be 0. so an s orbital has one configuration and can hold a maximum of 2 electrons.
so for the purposes of that problem you were given n = 2, l = 1 and mL = -1.
so we look at the quantum number, that's n = 2 and right away we know that it's either s or a p orbital. why? because d orbitals start at n = 3 and f orbitals start at n =4 and so on.
now we look at the shape of the orbital. this will give us a lot of information about what we're dealing with. in our case L = 1 which means that mL can be between positive 1 and negative one.
so we write out all our possible orientations given mL.
we have mL = 0
mL = -1
mL = 1
this means that there are three possible orientations of this orbital Px,Py, and Pz and each contains 2 electrons. so right away we know that this is an S orbital.
now so we know that this is a p orbital, and we know that n = 2. we also know that S can't share any of these orientations, as well as, D, and F. of n = 2. We need to find an atom that shares all of these quantum numbers. how about a mother p orbital. well? n = 2 would mean 2p if we go up to a higher energy level we start with n = 3. because all the quantum numbers are not the same we can only consider the case for n = 2. so knowing this can you see how many electrons would be in an atom that shares all of those quantum numbers?