## anonymous one year ago Two metal balls have charges of 7.1 * 10ÈÒ coulombs and 6.9 * 10ÈÒ coulombs. They are 5.7 * 10È¹ meters apart. What is the force of interaction between the two balls? (k = 9.0 * 10© newton·metersÆ/coulombÆ) a. 5.7 newtons b. 6.9 newtons c. 7.1 newtons d. 1.4 newton

1. IrishBoy123

use Coulombs law: $$\large F = k \frac{q_1 \ q_2}{r^2}$$

2. anonymous

can you just help me out with the answer? @IrishBoy123