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Abhisar
 one year ago
A man wishes to swim across a river 0.5 m wide. If he can swim at the rate of 2 Km/ h in still water and the river flows at the rate of 1 km/hr. The angle (wrt flow of water) along which he should swim so as to reach a point exactly opposite his starting point, should be?
Abhisar
 one year ago
A man wishes to swim across a river 0.5 m wide. If he can swim at the rate of 2 Km/ h in still water and the river flows at the rate of 1 km/hr. The angle (wrt flow of water) along which he should swim so as to reach a point exactly opposite his starting point, should be?

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imqwerty
 one year ago
Best ResponseYou've already chosen the best response.1really 0.5m wide river!!!

ChillOut
 one year ago
Best ResponseYou've already chosen the best response.1All right, let's draw that first.

Abhisar
 one year ago
Best ResponseYou've already chosen the best response.0Hahaha..nopes it should be 0.5 Km

ChillOut
 one year ago
Best ResponseYou've already chosen the best response.1dw:1437497187136:dw

ChillOut
 one year ago
Best ResponseYou've already chosen the best response.1dw:1437497254385:dw

Abhisar
 one year ago
Best ResponseYou've already chosen the best response.0\(\color{blue}{\text{Originally Posted by}}\) @imqwerty 30 degrees :) \(\color{blue}{\text{End of Quote}}\) No direct answers and btw it's incorrect ...

ChillOut
 one year ago
Best ResponseYou've already chosen the best response.1The net horizontal velocity must be equal 0, so \(v*cos( θ )1=0\)

ChillOut
 one year ago
Best ResponseYou've already chosen the best response.1Can you finish it, @imqwerty? :)

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.1let the man make angle theta with the direction opposite to the river flow his horizontal component of velocity = Velocity of man x cos(theta) = Vcos(theta)=2cos(theta) this should equal the velocity of river flow so as to reach the directly opposite point so 2cos(theta)=1 cos(theta)=1/2 theta=60 degrees

Abhisar
 one year ago
Best ResponseYou've already chosen the best response.0The man should swim across the line AO and you have to find angle AOD

ChillOut
 one year ago
Best ResponseYou've already chosen the best response.1Oh, right. I didn't read the part where it states it's the angle between the flow and the man xD

ChillOut
 one year ago
Best ResponseYou've already chosen the best response.1So it means that the angle must be in the second quadrant, 120 degrees.
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