Abhisar
  • Abhisar
A man wishes to swim across a river 0.5 m wide. If he can swim at the rate of 2 Km/ h in still water and the river flows at the rate of 1 km/hr. The angle (wrt flow of water) along which he should swim so as to reach a point exactly opposite his starting point, should be?
Mathematics
jamiebookeater
  • jamiebookeater
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imqwerty
  • imqwerty
really 0.5m wide river!!!
ChillOut
  • ChillOut
All right, let's draw that first.
Abhisar
  • Abhisar
Hahaha..nopes it should be 0.5 Km

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imqwerty
  • imqwerty
lol ok :)
ChillOut
  • ChillOut
|dw:1437497187136:dw|
ChillOut
  • ChillOut
|dw:1437497254385:dw|
imqwerty
  • imqwerty
60 degrees
Abhisar
  • Abhisar
\(\color{blue}{\text{Originally Posted by}}\) @imqwerty 30 degrees :) \(\color{blue}{\text{End of Quote}}\) No direct answers and btw it's incorrect ...
ChillOut
  • ChillOut
The net horizontal velocity must be equal 0, so \(v*cos( θ )-1=0\)
ChillOut
  • ChillOut
Can you finish it, @imqwerty? :)
imqwerty
  • imqwerty
let the man make angle theta with the direction opposite to the river flow his horizontal component of velocity = Velocity of man x cos(theta) = Vcos(theta)=2cos(theta) this should equal the velocity of river flow so as to reach the directly opposite point so 2cos(theta)=1 cos(theta)=1/2 theta=60 degrees
Abhisar
  • Abhisar
It's incorrect...
Abhisar
  • Abhisar
|dw:1437497568545:dw|
Abhisar
  • Abhisar
The man should swim across the line AO and you have to find angle AOD
Abhisar
  • Abhisar
Ring a bell?
ChillOut
  • ChillOut
Oh, right. I didn't read the part where it states it's the angle between the flow and the man xD
Abhisar
  • Abhisar
Yes, so ?
ChillOut
  • ChillOut
So it means that the angle must be in the second quadrant, 120 degrees.
Abhisar
  • Abhisar
That's correct!

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