anonymous
  • anonymous
If 2.0 liters of oxygen gas react with excess carbon monoxide at 273 K and 1.00 atm, how many liters of carbon dioxide can be produced under the same conditions? 2 CO (g) + O2 (g) yields 2 CO2 (g) 1.0 L 2.0 L 4.0 L 6.0 L
Chemistry
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
anonymous
  • anonymous
would it be d?
JFraser
  • JFraser
Nope. Look at the molar ratios from the reaction

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

JFraser
  • JFraser
One mole of \(O_2\) will produce two moles of \(CO_2\)
anonymous
  • anonymous
ik iget so b? @jfraser
JFraser
  • JFraser
Nope. 2L of \(O_2\) will produce \(twice\) that volume of \(CO_2\)
JFraser
  • JFraser
Always remember that balanced equations give \(ratios\), not absolute amounts to work with
anonymous
  • anonymous
oh so a thanks @jfraser
JFraser
  • JFraser
It's not a, you did the ratio backwards
Rushwr
  • Rushwr
@JFraser is it 4L?
Photon336
  • Photon336
the key here is that you know carbon monoxide is in excess, so essentially o2 is your limiting reagent and you have to use that to figure out how many moles of CO2 are produced. once you do that you can figure out the answer.

Looking for something else?

Not the answer you are looking for? Search for more explanations.