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nuccioreggie

  • one year ago

;elp

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  1. nuccioreggie
    • one year ago
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    @Michele_Laino. Please explain

  2. nuccioreggie
    • one year ago
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    @DanJS. P)ease explain. Both parts please

  3. DanJS
    • one year ago
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    To find the probability of hitting the black circle, you have to compare the area of the circle to the area of the white region

  4. DanJS
    • one year ago
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    They give you the diameter is 2, so the radius is 1, and the area of a circle is pi*r^2 = pi* 1 = pi

  5. DanJS
    • one year ago
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    The area of the white region , is the area of the square take away the area of the circle 100 - pi

  6. nuccioreggie
    • one year ago
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    Ok can u explain both answers please

  7. DanJS
    • one year ago
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    you get that part

  8. DanJS
    • one year ago
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    The probability of hitting the black circle is the ratio of the two areas... \[\frac{ Area~circle }{ Area~white } = \frac{ \pi }{ 100-\pi } \approx 0.032\]

  9. DanJS
    • one year ago
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    only about 3.2% chance

  10. DanJS
    • one year ago
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    0 is no chance, and 1 is garunteed 100% , so it is very much closer to zero than 1

  11. nuccioreggie
    • one year ago
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    So thats the answer for part A

  12. DanJS
    • one year ago
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    yea

  13. DanJS
    • one year ago
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    part b is less work, since you know the chance of hitting the circle is 0.032, then the chance of hitting the white area is 1 - (chance of circle) = 1 - 0.032 = much closer to 1 for the white region

  14. DanJS
    • one year ago
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    Because it is assumed he hits the board somewhere every throw , i guess, no missing

  15. DanJS
    • one year ago
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    so (chance circle) + (Chance white) = 1

  16. nuccioreggie
    • one year ago
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    Can you explain Part A again please

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