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anonymous
 one year ago
simplify radical 25
anonymous
 one year ago
simplify radical 25

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@TheSmartOne @JoannaBlackwelder

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1437498244836:dw

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2\[\huge\rm \sqrt{25}\] factor out 1 \[\huge\rm \sqrt{25} = \sqrt{1} \times \sqrt{25}\] and combine like terms 't the denominator

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What does \[\sqrt{25}\] simplify into? Hint: 25 is a perfect square.

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2and \[\sqrt{1} = ???\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2\[i = \sqrt{1}\] \[i^2 = 1\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2dw:1437498682455:dw now combine like terms (52i) +( 13i)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2so you can replace sqrt of 1 by i

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so what would the answer be?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0√25 simplifies to 5 and √1 simplifies to i and they multiply to make 5i

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2that's what you should find ot

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1437498844568:dw

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2and how did you get that ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0√25 simplifies to 5 and √1 simplifies to i and they multiply to make 5i

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2\(\color{blue}{\text{Originally Posted by}}\) @LorenaHue43 i got 5+20i/17 \(\color{blue}{\text{End of Quote}}\) \(\color{blue}{\text{Originally Posted by}}\) @Nnesha and how did you get that ? \(\color{blue}{\text{End of Quote}}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0*sighs* I jusy guessed bc i have no idea what to do

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2\[\huge\rm (52i)+(63i)\] combine like terms

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2alright now multiply denominator and numerator by the conjugate of (65i)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2\[\huge\rm (52i)+(13i)\] sorry abt that

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2yep numerator is 30i25i^2 so i^2 = 1 replace i^2 by 1

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2and what about the denominator ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2and btw what's the conjugate of 65i ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.06+5i is the conjugate

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2i have no idea how u got that ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2yes right \[\huge\rm \frac{ 5i(6+5i) }{ 65i(6+5i) }\] 5i times 5i = ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2yes right so \[\huge\rm \frac{ 30i + 25i^2 }{ 61 }\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2replace i^2 by 1 and done!

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2remember \[i =\sqrt{1}\] i^2 = 1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can I ask one more please? I have the answer this time lol:D

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2who gave u the answer ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1437499746192:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0simplify that please. I got 2/65/5 (idek where the radical sign is)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2what are factors of 24 ,45 and 20 ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.024=4,6 45=9,5 20=4,5

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2yes right dw:1437499992200:dw 4,9 ,4 are perfect square root

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So then I was right?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2multiply dw:1437500190222:dw multiply those numbers and there are common sqrt{5} so you can combine last two terms

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2what did you get ? sorry i was afk

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1437500682025:dw

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2did you use calculator ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2alright that's right but next time DON'T forget to post ur work thanks

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I have one more to ask. I really don't understand

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0\(\dfrac{\sqrt {25}} {(5  2i) + (1  3i)} \) \(= \dfrac{\sqrt {1} \sqrt{25}} {5  2i + 1  3i} \) \(= \dfrac{i \times 5} {6  5i} \) \(= \dfrac{5i} {6  5i} \times \dfrac{6 + 5i}{6 + 5i}\) \(= \dfrac{5i (6 + 5i)} {(6  5i)(6 + 5i)} \) \(=\dfrac{30i + 25i^2}{6^2  (5i)^2} \) \(= \dfrac{30i + 25(1)}{36  25(1)} \) \(=\dfrac{25 + 30i}{36 + 25} \) \(=\dfrac{25 + 30i}{61} \) \(= \dfrac{25}{61} + \dfrac{30}{61}i \)

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0dw:1437501142771:dw
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