anonymous
  • anonymous
simplify radical -25
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
@TheSmartOne @JoannaBlackwelder
anonymous
  • anonymous
|dw:1437498244836:dw|
Nnesha
  • Nnesha
\[\huge\rm \sqrt{-25}\] factor out -1 \[\huge\rm \sqrt{-25} = \sqrt{-1} \times \sqrt{25}\] and combine like terms 't the denominator

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More answers

anonymous
  • anonymous
What does \[\sqrt{-25}\] simplify into? Hint: 25 is a perfect square.
anonymous
  • anonymous
5
Nnesha
  • Nnesha
and \[\sqrt{-1} = ???\]
anonymous
  • anonymous
idek
Nnesha
  • Nnesha
\[i = \sqrt{-1}\] \[i^2 = -1\]
anonymous
  • anonymous
so now what
anonymous
  • anonymous
√-1=i
Nnesha
  • Nnesha
|dw:1437498682455:dw| now combine like terms (5-2i) +( 1-3i)
anonymous
  • anonymous
5i
Nnesha
  • Nnesha
so you can replace sqrt of -1 by i
anonymous
  • anonymous
so what would the answer be?
anonymous
  • anonymous
√25 simplifies to 5 and √-1 simplifies to i and they multiply to make 5i
anonymous
  • anonymous
got that?
Nnesha
  • Nnesha
that's what you should find ot
anonymous
  • anonymous
|dw:1437498844568:dw|
anonymous
  • anonymous
i got 5+20i/17
anonymous
  • anonymous
its 5i
anonymous
  • anonymous
T^T
Nnesha
  • Nnesha
and how did you get that ?
anonymous
  • anonymous
√25 simplifies to 5 and √-1 simplifies to i and they multiply to make 5i
Nnesha
  • Nnesha
\(\color{blue}{\text{Originally Posted by}}\) @LorenaHue43 i got 5+20i/17 \(\color{blue}{\text{End of Quote}}\) \(\color{blue}{\text{Originally Posted by}}\) @Nnesha and how did you get that ? \(\color{blue}{\text{End of Quote}}\)
anonymous
  • anonymous
*sighs* I jusy guessed bc i have no idea what to do
anonymous
  • anonymous
I got 5i/(6-5i)
Nnesha
  • Nnesha
\[\huge\rm (5-2i)+(6-3i)\] combine like terms
anonymous
  • anonymous
no it is (1-3i)
Nnesha
  • Nnesha
alright now multiply denominator and numerator by the conjugate of (6-5i)
Nnesha
  • Nnesha
\[\huge\rm (5-2i)+(1-3i)\] sorry abt that
anonymous
  • anonymous
30i-25i^2
Nnesha
  • Nnesha
yep numerator is 30i-25i^2 so i^2 = -1 replace i^2 by -1
Nnesha
  • Nnesha
and what about the denominator ?
Nnesha
  • Nnesha
and btw what's the conjugate of 6-5i ?
anonymous
  • anonymous
36-60i-25i2
anonymous
  • anonymous
6+5i is the conjugate
Nnesha
  • Nnesha
i have no idea how u got that ?
Nnesha
  • Nnesha
yes right \[\huge\rm \frac{ 5i(6+5i) }{ 6-5i(6+5i) }\] 5i times 5i = ?
anonymous
  • anonymous
25i2
anonymous
  • anonymous
61
Nnesha
  • Nnesha
yes right so \[\huge\rm \frac{ 30i + 25i^2 }{ 61 }\]
Nnesha
  • Nnesha
replace i^2 by -1 and done!
anonymous
  • anonymous
soo -25+30i/61
Nnesha
  • Nnesha
remember \[i =\sqrt{-1}\] i^2 = -1
Nnesha
  • Nnesha
yes right
anonymous
  • anonymous
Can I ask one more please? I have the answer this time lol:D
Nnesha
  • Nnesha
who gave u the answer ?
anonymous
  • anonymous
I solved it..
Nnesha
  • Nnesha
alright.
anonymous
  • anonymous
|dw:1437499746192:dw|
anonymous
  • anonymous
simplify that please. I got 2/6-5/5 (idek where the radical sign is)
Nnesha
  • Nnesha
what are factors of 24 ,45 and 20 ?
anonymous
  • anonymous
24=4,6 45=9,5 20=4,5
Nnesha
  • Nnesha
yes right |dw:1437499992200:dw| 4,9 ,4 are perfect square root
anonymous
  • anonymous
So then I was right?
Nnesha
  • Nnesha
multiply |dw:1437500190222:dw| multiply those numbers and there are common sqrt{5} so you can combine last two terms
Nnesha
  • Nnesha
what did you get ? sorry i was afk
anonymous
  • anonymous
|dw:1437500682025:dw|
Nnesha
  • Nnesha
did you use calculator ?
anonymous
  • anonymous
no,
Nnesha
  • Nnesha
alright that's right but next time DON'T forget to post ur work thanks
anonymous
  • anonymous
:) Thank you!
anonymous
  • anonymous
I have one more to ask. I really don't understand
Nnesha
  • Nnesha
make a new post
anonymous
  • anonymous
will do
mathstudent55
  • mathstudent55
\(\dfrac{\sqrt {-25}} {(5 - 2i) + (1 - 3i)} \) \(= \dfrac{\sqrt {-1} \sqrt{25}} {5 - 2i + 1 - 3i} \) \(= \dfrac{i \times 5} {6 - 5i} \) \(= \dfrac{5i} {6 - 5i} \times \dfrac{6 + 5i}{6 + 5i}\) \(= \dfrac{5i (6 + 5i)} {(6 - 5i)(6 + 5i)} \) \(=\dfrac{30i + 25i^2}{6^2 - (5i)^2} \) \(= \dfrac{30i + 25(-1)}{36 - 25(-1)} \) \(=\dfrac{-25 + 30i}{36 + 25} \) \(=\dfrac{-25 + 30i}{61} \) \(= -\dfrac{25}{61} + \dfrac{30}{61}i \)
mathstudent55
  • mathstudent55
|dw:1437501142771:dw|

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