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anonymous

  • one year ago

simplify radical -25

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  1. anonymous
    • one year ago
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    @TheSmartOne @JoannaBlackwelder

  2. anonymous
    • one year ago
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    |dw:1437498244836:dw|

  3. Nnesha
    • one year ago
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    \[\huge\rm \sqrt{-25}\] factor out -1 \[\huge\rm \sqrt{-25} = \sqrt{-1} \times \sqrt{25}\] and combine like terms 't the denominator

  4. anonymous
    • one year ago
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    What does \[\sqrt{-25}\] simplify into? Hint: 25 is a perfect square.

  5. anonymous
    • one year ago
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    5

  6. Nnesha
    • one year ago
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    and \[\sqrt{-1} = ???\]

  7. anonymous
    • one year ago
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    idek

  8. Nnesha
    • one year ago
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    \[i = \sqrt{-1}\] \[i^2 = -1\]

  9. anonymous
    • one year ago
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    so now what

  10. anonymous
    • one year ago
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    √-1=i

  11. Nnesha
    • one year ago
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    |dw:1437498682455:dw| now combine like terms (5-2i) +( 1-3i)

  12. anonymous
    • one year ago
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    5i

  13. Nnesha
    • one year ago
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    so you can replace sqrt of -1 by i

  14. anonymous
    • one year ago
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    so what would the answer be?

  15. anonymous
    • one year ago
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    √25 simplifies to 5 and √-1 simplifies to i and they multiply to make 5i

  16. anonymous
    • one year ago
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    got that?

  17. Nnesha
    • one year ago
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    that's what you should find ot

  18. anonymous
    • one year ago
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    |dw:1437498844568:dw|

  19. anonymous
    • one year ago
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    i got 5+20i/17

  20. anonymous
    • one year ago
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    its 5i

  21. anonymous
    • one year ago
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    T^T

  22. Nnesha
    • one year ago
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    and how did you get that ?

  23. anonymous
    • one year ago
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    √25 simplifies to 5 and √-1 simplifies to i and they multiply to make 5i

  24. Nnesha
    • one year ago
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    \(\color{blue}{\text{Originally Posted by}}\) @LorenaHue43 i got 5+20i/17 \(\color{blue}{\text{End of Quote}}\) \(\color{blue}{\text{Originally Posted by}}\) @Nnesha and how did you get that ? \(\color{blue}{\text{End of Quote}}\)

  25. anonymous
    • one year ago
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    *sighs* I jusy guessed bc i have no idea what to do

  26. anonymous
    • one year ago
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    I got 5i/(6-5i)

  27. Nnesha
    • one year ago
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    \[\huge\rm (5-2i)+(6-3i)\] combine like terms

  28. anonymous
    • one year ago
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    no it is (1-3i)

  29. Nnesha
    • one year ago
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    alright now multiply denominator and numerator by the conjugate of (6-5i)

  30. Nnesha
    • one year ago
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    \[\huge\rm (5-2i)+(1-3i)\] sorry abt that

  31. anonymous
    • one year ago
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    30i-25i^2

  32. Nnesha
    • one year ago
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    yep numerator is 30i-25i^2 so i^2 = -1 replace i^2 by -1

  33. Nnesha
    • one year ago
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    and what about the denominator ?

  34. Nnesha
    • one year ago
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    and btw what's the conjugate of 6-5i ?

  35. anonymous
    • one year ago
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    36-60i-25i2

  36. anonymous
    • one year ago
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    6+5i is the conjugate

  37. Nnesha
    • one year ago
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    i have no idea how u got that ?

  38. Nnesha
    • one year ago
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    yes right \[\huge\rm \frac{ 5i(6+5i) }{ 6-5i(6+5i) }\] 5i times 5i = ?

  39. anonymous
    • one year ago
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    25i2

  40. anonymous
    • one year ago
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    61

  41. Nnesha
    • one year ago
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    yes right so \[\huge\rm \frac{ 30i + 25i^2 }{ 61 }\]

  42. Nnesha
    • one year ago
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    replace i^2 by -1 and done!

  43. anonymous
    • one year ago
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    soo -25+30i/61

  44. Nnesha
    • one year ago
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    remember \[i =\sqrt{-1}\] i^2 = -1

  45. Nnesha
    • one year ago
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    yes right

  46. anonymous
    • one year ago
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    Can I ask one more please? I have the answer this time lol:D

  47. Nnesha
    • one year ago
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    who gave u the answer ?

  48. anonymous
    • one year ago
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    I solved it..

  49. Nnesha
    • one year ago
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    alright.

  50. anonymous
    • one year ago
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    |dw:1437499746192:dw|

  51. anonymous
    • one year ago
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    simplify that please. I got 2/6-5/5 (idek where the radical sign is)

  52. Nnesha
    • one year ago
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    what are factors of 24 ,45 and 20 ?

  53. anonymous
    • one year ago
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    24=4,6 45=9,5 20=4,5

  54. Nnesha
    • one year ago
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    yes right |dw:1437499992200:dw| 4,9 ,4 are perfect square root

  55. anonymous
    • one year ago
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    So then I was right?

  56. Nnesha
    • one year ago
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    multiply |dw:1437500190222:dw| multiply those numbers and there are common sqrt{5} so you can combine last two terms

  57. Nnesha
    • one year ago
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    what did you get ? sorry i was afk

  58. anonymous
    • one year ago
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    |dw:1437500682025:dw|

  59. Nnesha
    • one year ago
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    did you use calculator ?

  60. anonymous
    • one year ago
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    no,

  61. Nnesha
    • one year ago
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    alright that's right but next time DON'T forget to post ur work thanks

  62. anonymous
    • one year ago
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    :) Thank you!

  63. anonymous
    • one year ago
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    I have one more to ask. I really don't understand

  64. Nnesha
    • one year ago
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    make a new post

  65. anonymous
    • one year ago
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    will do

  66. mathstudent55
    • one year ago
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    \(\dfrac{\sqrt {-25}} {(5 - 2i) + (1 - 3i)} \) \(= \dfrac{\sqrt {-1} \sqrt{25}} {5 - 2i + 1 - 3i} \) \(= \dfrac{i \times 5} {6 - 5i} \) \(= \dfrac{5i} {6 - 5i} \times \dfrac{6 + 5i}{6 + 5i}\) \(= \dfrac{5i (6 + 5i)} {(6 - 5i)(6 + 5i)} \) \(=\dfrac{30i + 25i^2}{6^2 - (5i)^2} \) \(= \dfrac{30i + 25(-1)}{36 - 25(-1)} \) \(=\dfrac{-25 + 30i}{36 + 25} \) \(=\dfrac{-25 + 30i}{61} \) \(= -\dfrac{25}{61} + \dfrac{30}{61}i \)

  67. mathstudent55
    • one year ago
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    |dw:1437501142771:dw|

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