***WILL MEDAL*** You have two exponential functions. One has the formula h(x) = -2 x + 8. The other function, g(x), has the graph shown below. https://gordon.owschools.com/media/o_anageo_ccss_2014/8/alg1_9_20_34_exponential.gif Which inequality below is true on the indicated interval? A. g(x) ≥ h(x) on the interval -2 ≤ x ≤ -1 B. h(x) ≤ g(x) on the interval -1 ≤ x ≤ 0 C. g(x) ≥ h(x) on the interval 0 ≤ x ≤ 1 D. h(x) ≤ g(x) on the interval 1 ≤ x ≤ 2

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***WILL MEDAL*** You have two exponential functions. One has the formula h(x) = -2 x + 8. The other function, g(x), has the graph shown below. https://gordon.owschools.com/media/o_anageo_ccss_2014/8/alg1_9_20_34_exponential.gif Which inequality below is true on the indicated interval? A. g(x) ≥ h(x) on the interval -2 ≤ x ≤ -1 B. h(x) ≤ g(x) on the interval -1 ≤ x ≤ 0 C. g(x) ≥ h(x) on the interval 0 ≤ x ≤ 1 D. h(x) ≤ g(x) on the interval 1 ≤ x ≤ 2

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Is h(x) \(2^{x}+8\)?

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i think so
Because it'll be completely different if it's \(2^{x+8}\)
i think its the first one
All right... So let's find g(x)'s equation. Since we know it is an exponential function, it has the following form: \(a^{x}+z\). For the first and easiest part, we can find z by simply making x=0. This gives z=3, which is the "y intercept".
My guess is D...?
Are you guessing or did ou try to finish it? xD
All right, moving on... So to find a, we just make x=1, so we have g(1)=a+3, and since we have the value of g(1), which is 6, we can do the following: \(6=a^{1}+3,a=3\). So we have \(g(x)=3^{x}+3,\)
This is just confusing me...
I'm just finding the equation for g(x). Now I can keep moving on the problem
okay
Oh god, I've found an major error. But all right, I'll redo, with the same steps.
g(x)=\(a^{x}+z\) g(0)=3, so 1+z= 3, z=2. g(1)=6, so a + 2=6 and a=4 We have \(g(x)=4^{x}+2\)
Now we test the options... Just plug in the values in the fuctions and check if the statements are true or false! Can you do that?
yes! thank you.
No problem!
I'm still here if you get stuck.
im still getting D
All right, let me check, one moment.
It seems you're right. g(1) = 6, f(1) = 6 g(2) = 18, f(2) = 4 So g(1)=f(1) and g(2)>f(2).
Okay thank you
No problem. If you need help, just ask.
okay

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