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anonymous

  • one year ago

Solve 3x2 + 6x + 15 = 0

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  1. anonymous
    • one year ago
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    @mathstudent55

  2. anonymous
    • one year ago
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    @welshfella

  3. anonymous
    • one year ago
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    standered form

  4. anonymous
    • one year ago
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    no using the quad. equation

  5. anonymous
    • one year ago
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    oh x=−1±2i

  6. welshfella
    • one year ago
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    divide through by 3;- 3(x^2+2x+5) = 0

  7. welshfella
    • one year ago
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    @jamese please don't give direct answers

  8. anonymous
    • one year ago
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    Thanks:)

  9. welshfella
    • one year ago
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    this won't factor so you can use the quadratic formula

  10. anonymous
    • one year ago
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    I did. and then I got -6 + or negativd radical 144

  11. anonymous
    • one year ago
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    then you simplify|dw:1437503232700:dw|

  12. welshfella
    • one year ago
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    it would be simpler to solve what in the parentheses x^2 + 2x + 5 = 0

  13. anonymous
    • one year ago
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    Then i got -1 plus/neg 2i

  14. anonymous
    • one year ago
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    ight but i cant help it i like it

  15. welshfella
    • one year ago
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    |dw:1437503348625:dw|

  16. welshfella
    • one year ago
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    @jamest - you risk being supended

  17. anonymous
    • one year ago
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    then for rad. 20 you get 4, 5 which can be simplified to 2 radical 5

  18. welshfella
    • one year ago
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    |dw:1437503520235:dw|

  19. welshfella
    • one year ago
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    now one more simplification and you have it

  20. mathstudent55
    • one year ago
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    \(3x2 + 6x + 15 = 0\) \(x^2 + 2x + 5 = 0\) \(x = \dfrac{-b \pm \sqrt {b^2 - 4ac}}{2a} \) \(x = \dfrac{-2 \pm \sqrt {2^2 - 4(1)(5)}}{2(1)} \) \(x = \dfrac{-2 \pm \sqrt {4 - 20}}{2} \) \(x = \dfrac{-2 \pm \sqrt {- 16}}{2} \) \(x = \dfrac{-2 \pm 4i}{2} \) \(x = -1 \pm 2i \)

  21. anonymous
    • one year ago
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    ight thx for lettin me know

  22. anonymous
    • one year ago
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    Thanks:) !

  23. welshfella
    • one year ago
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    oops - sorry - i goofed up on the i on!

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