anonymous
  • anonymous
Solve 3x2 + 6x + 15 = 0
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
@mathstudent55
anonymous
  • anonymous
@welshfella
anonymous
  • anonymous
standered form

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anonymous
  • anonymous
no using the quad. equation
anonymous
  • anonymous
oh x=−1±2i
welshfella
  • welshfella
divide through by 3;- 3(x^2+2x+5) = 0
welshfella
  • welshfella
@jamese please don't give direct answers
anonymous
  • anonymous
Thanks:)
welshfella
  • welshfella
this won't factor so you can use the quadratic formula
anonymous
  • anonymous
I did. and then I got -6 + or negativd radical 144
anonymous
  • anonymous
then you simplify|dw:1437503232700:dw|
welshfella
  • welshfella
it would be simpler to solve what in the parentheses x^2 + 2x + 5 = 0
anonymous
  • anonymous
Then i got -1 plus/neg 2i
anonymous
  • anonymous
ight but i cant help it i like it
welshfella
  • welshfella
|dw:1437503348625:dw|
welshfella
  • welshfella
@jamest - you risk being supended
anonymous
  • anonymous
then for rad. 20 you get 4, 5 which can be simplified to 2 radical 5
welshfella
  • welshfella
|dw:1437503520235:dw|
welshfella
  • welshfella
now one more simplification and you have it
mathstudent55
  • mathstudent55
\(3x2 + 6x + 15 = 0\) \(x^2 + 2x + 5 = 0\) \(x = \dfrac{-b \pm \sqrt {b^2 - 4ac}}{2a} \) \(x = \dfrac{-2 \pm \sqrt {2^2 - 4(1)(5)}}{2(1)} \) \(x = \dfrac{-2 \pm \sqrt {4 - 20}}{2} \) \(x = \dfrac{-2 \pm \sqrt {- 16}}{2} \) \(x = \dfrac{-2 \pm 4i}{2} \) \(x = -1 \pm 2i \)
anonymous
  • anonymous
ight thx for lettin me know
anonymous
  • anonymous
Thanks:) !
welshfella
  • welshfella
oops - sorry - i goofed up on the i on!

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