anonymous
  • anonymous
What is the period? \( \huge y = 10 \sin(\frac{2\pi}{365}(x-50)) \) Is the period \( \huge frac{2\pi}{\frac{2\pi}{365}} \) which would be 365??
Mathematics
  • Stacey Warren - Expert brainly.com
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schrodinger
  • schrodinger
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anonymous
  • anonymous
What is the period? \( \huge y = 10 \sin(\frac{2\pi}{365}(x-50)) \) Is the period \( \huge \frac{2\pi}{\frac{2\pi}{365}} \) which would be 365??
anonymous
  • anonymous
@phi
phi
  • phi
if you manipulate the coeff of x into the form \[ \frac{2\pi}{T} x \] then T is the period

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phi
  • phi
you have 2pi/365 the 365 matches T so yes, the period is 365
anonymous
  • anonymous
Ok, so 365 is T so does the 50 compress the period?
anonymous
  • anonymous
Or is shifts it to the left
phi
  • phi
no the -50 * 2pi/365 is a phase shift (moves the curve to the right)
anonymous
  • anonymous
Ok thanks so we have T = 365 with a phase shift to the right
phi
  • phi
the red curve is the sin without the -50 term the black curve is yours.
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anonymous
  • anonymous
Thank you!

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