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anonymous
 one year ago
What is the period?
\( \huge y = 10 \sin(\frac{2\pi}{365}(x50)) \)
Is the period \( \huge frac{2\pi}{\frac{2\pi}{365}} \) which would be 365??
anonymous
 one year ago
What is the period? \( \huge y = 10 \sin(\frac{2\pi}{365}(x50)) \) Is the period \( \huge frac{2\pi}{\frac{2\pi}{365}} \) which would be 365??

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What is the period? \( \huge y = 10 \sin(\frac{2\pi}{365}(x50)) \) Is the period \( \huge \frac{2\pi}{\frac{2\pi}{365}} \) which would be 365??

phi
 one year ago
Best ResponseYou've already chosen the best response.2if you manipulate the coeff of x into the form \[ \frac{2\pi}{T} x \] then T is the period

phi
 one year ago
Best ResponseYou've already chosen the best response.2you have 2pi/365 the 365 matches T so yes, the period is 365

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok, so 365 is T so does the 50 compress the period?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Or is shifts it to the left

phi
 one year ago
Best ResponseYou've already chosen the best response.2no the 50 * 2pi/365 is a phase shift (moves the curve to the right)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok thanks so we have T = 365 with a phase shift to the right

phi
 one year ago
Best ResponseYou've already chosen the best response.2the red curve is the sin without the 50 term the black curve is yours.
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