anonymous
  • anonymous
What is the period? \( \huge y = 10 \sin(\frac{2\pi}{365}(x-50)) \) Is the period \( \huge frac{2\pi}{\frac{2\pi}{365}} \) which would be 365??
Mathematics
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
What is the period? \( \huge y = 10 \sin(\frac{2\pi}{365}(x-50)) \) Is the period \( \huge \frac{2\pi}{\frac{2\pi}{365}} \) which would be 365??
anonymous
  • anonymous
phi
  • phi
if you manipulate the coeff of x into the form \[ \frac{2\pi}{T} x \] then T is the period

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

phi
  • phi
you have 2pi/365 the 365 matches T so yes, the period is 365
anonymous
  • anonymous
Ok, so 365 is T so does the 50 compress the period?
anonymous
  • anonymous
Or is shifts it to the left
phi
  • phi
no the -50 * 2pi/365 is a phase shift (moves the curve to the right)
anonymous
  • anonymous
Ok thanks so we have T = 365 with a phase shift to the right
phi
  • phi
the red curve is the sin without the -50 term the black curve is yours.
1 Attachment
anonymous
  • anonymous
Thank you!

Looking for something else?

Not the answer you are looking for? Search for more explanations.