## anonymous one year ago What is the period? $$\huge y = 10 \sin(\frac{2\pi}{365}(x-50))$$ Is the period $$\huge frac{2\pi}{\frac{2\pi}{365}}$$ which would be 365??

1. anonymous

What is the period? $$\huge y = 10 \sin(\frac{2\pi}{365}(x-50))$$ Is the period $$\huge \frac{2\pi}{\frac{2\pi}{365}}$$ which would be 365??

2. anonymous

@phi

3. phi

if you manipulate the coeff of x into the form $\frac{2\pi}{T} x$ then T is the period

4. phi

you have 2pi/365 the 365 matches T so yes, the period is 365

5. anonymous

Ok, so 365 is T so does the 50 compress the period?

6. anonymous

Or is shifts it to the left

7. phi

no the -50 * 2pi/365 is a phase shift (moves the curve to the right)

8. anonymous

Ok thanks so we have T = 365 with a phase shift to the right

9. phi

the red curve is the sin without the -50 term the black curve is yours.

10. anonymous

Thank you!