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anonymous
 one year ago
Which of the following points (x, y, z) is in the solution set of the system of inequalities:
x + 3y − z ≤ 5
x − 2z ≥ 0
x + y + z ≤ 10
(a) (1, 1, 3)
(b) (2, 2, 1)
(c) (6, −2, 2)
(d) (8, 3, 1)
(e) (−1, 8, −2)
(f) None of these
please explain as well :) Thank you
anonymous
 one year ago
Which of the following points (x, y, z) is in the solution set of the system of inequalities: x + 3y − z ≤ 5 x − 2z ≥ 0 x + y + z ≤ 10 (a) (1, 1, 3) (b) (2, 2, 1) (c) (6, −2, 2) (d) (8, 3, 1) (e) (−1, 8, −2) (f) None of these please explain as well :) Thank you

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freckles
 one year ago
Best ResponseYou've already chosen the best response.1you could enter in the choices and see which satisfies the inequalities

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so (c) is correct answer?

freckles
 one year ago
Best ResponseYou've already chosen the best response.1let's check (6,2,2) x=6 y=2 z=2 \[6+3(2)2 \le 5 \\ 662 \le 5 \\ 2 \le 5 \text{ the first inequality is true } 2 \text{ is less than } 5 \\ 62(2) \ge 0 \\ 64 \ge 0 \\ 2 \ge 0 \text{ the second inequality is true 2 is greater than 0 } \\ 62+2 \le 10 \\ 6 \le 10 \text{ the third inequality is true 6 is less than 10 }\] so yes (6,2,2) seems to check out

freckles
 one year ago
Best ResponseYou've already chosen the best response.1can there be more than one option?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think that's the only one..

freckles
 one year ago
Best ResponseYou've already chosen the best response.1checking (1,1,3) \[1+33 \le 5 \\1 \le 5 \text{ first inequality true }\] \[12(3) \ge 0 \\ 16 \ge 0 \\ 5 \ge 0 \text{ \not true }\] no need to check third inequality (1,1,3) is not a solution checking (2,2,1) \[2+61 \le 5 \text{ is false }\] no need to check the other inequalities (2,2,1) is not a solution checking (8,3,1) \[8+91 \le 5 \text{ is false } \\ (8,3,1) \text{ doesn't work }\] checking (1,8,2) \[1+3(8)+2 \le 5 \text{ is false } \\ (1,8,2) \text{ is \not a solution }\] most of those choices fail at the first inequality
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