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anonymous

  • one year ago

Find the domain of the function f of x equals the square root of the quantity x minus 2, plus three A. x > or equal to 2 B. x < -2 C. x > 2 D. x > or equal to 2

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  1. anonymous
    • one year ago
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    @welshfella @mathstudent55

  2. welshfella
    • one year ago
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    f(x) = sqrt(x - 2) + 3

  3. welshfella
    • one year ago
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    the domain is the possible values of x - now we have another square root here and x - 2 cannot be negative - so what values of x - 2 make it greater than or equal to zero?

  4. anonymous
    • one year ago
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    3?

  5. welshfella
    • one year ago
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    we are looking for a range ov values not one value what we are doing really is solving the inequality x - 2 >= 0

  6. anonymous
    • one year ago
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    so its A?

  7. welshfella
    • one year ago
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    yes x >= 2 A

  8. welshfella
    • one year ago
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    D is the same thing - maybe theres a typ there

  9. anonymous
    • one year ago
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    yeah it was supposed to be -2 for D haha

  10. welshfella
    • one year ago
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    ok well i gotta go hope you understand better now

  11. anonymous
    • one year ago
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    thanks for the help means a lot

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