The graph shows two lines, A and B. Part A: How many solutions does the pair of equations for lines A and B have? Explain your answer. (5 points) Part B: What is the solution to the equations of lines A and B? Explain your answer.

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The graph shows two lines, A and B. Part A: How many solutions does the pair of equations for lines A and B have? Explain your answer. (5 points) Part B: What is the solution to the equations of lines A and B? Explain your answer.

Mathematics
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for part A--- how many times do the lines intersect... that is how many solutions exist

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Other answers:

part B--- just read off the point where the lines intersect
it intersects once
^^
so that is part A done... part B what is the point of intersection
thats where i get confused
u go to the right first
ok... so the x value is 1st followed by the y value... what is the x value where the lines intersect
then go up
if the coordinates were (4, 6) then u would go over 4 and go up 6
I'll let others help you to avoid to many responses at once
|dw:1437509032911:dw|
maybe this can help http://www.wikihow.com/Graph-Points-on-the-Coordinate-Plane
:)
so 4?
not quite
a coordinate has 2 #s
(3,4)?
that's right! @Austin.58
thats part b?
yes! the ordered pair is requested in part B
Thank you! Can you please help me with one more
:)
ok!
Mike and his friends bought cheese wafers for $2 per packet and chocolate wafers for $1 per packet at a carnival. They spent a total of $25 to buy a total of 20 packets of wafers of the two varieties. Part A: Write a system of equations that can be solved to find the number of packets of cheese wafers and the number of packets of chocolate wafers that Mike and his friends bought at the carnival. Define the variables used in the equations. (5 points) Part B: How many packets of chocolate wafers and cheese wafers did they buy? Explain how you got the answer and why you selected a particular method to get the answer. (5 points)
the algebraic system which model your problem is: \[\left\{ \begin{gathered} 2x + y = 25 \hfill \\ x + y = 20 \hfill \\ \end{gathered} \right.\]
where x ia the number of packets of chees wafers, whereas y is the numbers of packets of chocolate wafers
cheese*
the first equation takes into account for total cost the second one takes into account for total number of packets of wafer
so whats part a?
the answer of part A is my system above, with the meaning of the variable x, and y, and the meaning of both equations as I wrote
so the algebraic system is part a?
yes! please you have to keep in mind also the meaning of x and y
okay so now moving on to part b?
yes! we can solve your system using the elimination method, namely we solve the second equation with respect to the variable y, so we get: \[y = 20 - x\]
then I substitute into the first equation, so i can write this: \[2x + 20 - x = 25\]
so thats part b?
solving taht equation for x, I get: x=5
substituting x=5 into the equation for y, I get: y=20-x=20-5=15
so the solution is: x=5, y=15 that is the answer for part B

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