anonymous
  • anonymous
Tristen and gorge are stuck simplifying radical expressions. Tristren has to simplify . William has to simplify . Using full sentences, describe how to fully simplify Vanessa and William's expressions. Describe if Tristena dn George started with equivalent expressions or if they started with expressions that are not equal?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
they are the same equations...
anonymous
  • anonymous
@Michele_Laino
Michele_Laino
  • Michele_Laino
Vanessa will simplify as below: \[{x^{4/3 - 5/6}} = {x^{3/6}} = {x^{1/2}} = \sqrt x \]

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More answers

Michele_Laino
  • Michele_Laino
William will simplify as below: \[\sqrt[{16}]{{{x^{1 + 3 + 4}}}} = \sqrt[{16}]{{{x^8}}} = {x^{8/16}} = {x^{1/2}} = \sqrt x \]
anonymous
  • anonymous
for vanessesa isn't it saying to divide?
Michele_Laino
  • Michele_Laino
yes! infact I have computed the difference between exponents
anonymous
  • anonymous
okay:)
anonymous
  • anonymous
Can you help with this one?
Michele_Laino
  • Michele_Laino
ok!
Michele_Laino
  • Michele_Laino
let's suppose that the graph of f(x) is: |dw:1437512461162:dw|
Michele_Laino
  • Michele_Laino
namely f(0)=5
anonymous
  • anonymous
Yes
Michele_Laino
  • Michele_Laino
here is the graph of f(x)+2: |dw:1437512550200:dw|
anonymous
  • anonymous
I see
Michele_Laino
  • Michele_Laino
here is the graph of -2*f(x): |dw:1437512657609:dw|
Michele_Laino
  • Michele_Laino
namely if g(x)=-2*f(x), then: g(0)=-10
anonymous
  • anonymous
@Michele_Laino so where would it be increasing
Michele_Laino
  • Michele_Laino
the y-intercept for f(x)+2 is greater than the y-intercept of f(x)
Michele_Laino
  • Michele_Laino
whereas the y-intercept of g(x)=-2*f(x), is less than the y-intercept of f(x), if the y-intercept of f(x) is positive, and viceversa if the y-intercept of f(x) is negative
anonymous
  • anonymous
How did you get that answer?
anonymous
  • anonymous
isn't it -1/2 times f(x)
Michele_Laino
  • Michele_Laino
for example if the y-intercept of f(x) is 5, as in my drawing, then the y-intercept of -2*f(x), is -2*5=-10<5
Michele_Laino
  • Michele_Laino
oh sorry, I have made an error, I have considered the function -2*f(x) I have to consider the function -0.5 * f(x). here is the right drawing: |dw:1437513335915:dw|
Michele_Laino
  • Michele_Laino
the y-intercept of g(x)=-0.5*f(x), is less than the y-intercept of f(x), if the y-intercept of f(x) is positive, and viceversa if the y-intercept of f(x) is negative
Michele_Laino
  • Michele_Laino
for example if the y-intercept of f(x) is 5, as in my drawing, then the y-intercept of -0.5*f(x), is -2.5 <5
anonymous
  • anonymous
what about where the graphs are increasing/decreasing. I mean the points
Michele_Laino
  • Michele_Laino
whereas if the y-intercept of f(x) is -7, then the y-intercept of -0.5*f(x), is: -0.5*(-7)=3.5 > -7
Michele_Laino
  • Michele_Laino
as you can see from m,y last drawing, if f(x) increases also f(x)+2 increases, whereas if f(x) increases, then g(x)=-0.5*f(x) decreases
Michele_Laino
  • Michele_Laino
oops..from my* last drawing...
anonymous
  • anonymous
okay hahah! I see
Michele_Laino
  • Michele_Laino
I'm very sorry, it is 23:21 from me (Italy time zone) and I have to go to sleep
anonymous
  • anonymous
Aww :( OK! I'll see if I can find someone else. Byeee<3
anonymous
  • anonymous
Thanks so much!!!!
Michele_Laino
  • Michele_Laino
bye :) :)
Michele_Laino
  • Michele_Laino
thanks! :) :)

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