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  • one year ago

Suppose a straight 2.00 mm -diameter copper wire could just "float" horizontally in air because of the force due to the Earth's magnetic field B⃗ , which is horizontal, perpendicular to the wire, and of magnitude 6.9×10−5 T . A)What current would the wire carry?

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  1. IrishBoy123
    • one year ago
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    for the magnitude of the force due to the mag field you will need \(F = B \ I \ l\) as the current and field are at right angles. ie F = Mag field strength * Current * Length. balance that against gravity, you will need to find the density of copper.

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