anonymous
  • anonymous
Given that the heights and the volumes of the two solids are equivalent, find the diameter of the cylinder. Round your answer to the nearest hundredth
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
A) 2.13mm B) 2.31 mm C) 4.17mm D) 4.27mm
triciaal
  • triciaal
|dw:1437511958025:dw|

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anonymous
  • anonymous
\[\large \sf Volume~of~rectangular~prism\]\[\large \sf V~=~l \times w \times h\] \[\large \sf Volume~of~cylinder\]\[\large \sf V~=~\pi r^{2} h\]
triciaal
  • triciaal
diameter is twice the radius, r
anonymous
  • anonymous
idk the radius
anonymous
  • anonymous
Find the volume of the rectangular prism. Put that volume into the cylinder's formula and solve for the radius.
anonymous
  • anonymous
i got 121.635
anonymous
  • anonymous
And that's the volume. So now solve for the radius.
anonymous
  • anonymous
how do i get the radius
anonymous
  • anonymous
\[\large \sf V~=~ \pi r^{2} h\\\large \sf 121.635~=~ \pi r^{2} 8.5\] get r alone
anonymous
  • anonymous
I don't know how to get R alone
anonymous
  • anonymous
Do you know how to get x alone in \[\large \sf 5x~=~25\]?
anonymous
  • anonymous
yes
anonymous
  • anonymous
What's different about getting r alone?
anonymous
  • anonymous
its harder i dont know how to put it into pie
anonymous
  • anonymous
\[\large \sf 121.635~=~r^{2} \times 8.5 \pi\]
anonymous
  • anonymous
How about that? Can you get the \(r^{2}\) alone?
anonymous
  • anonymous
−∞,∞) {r|r∈R}
anonymous
  • anonymous
What?
anonymous
  • anonymous
i plugged that into the calculator and thats what i got
anonymous
  • anonymous
But that's completely unrelated...
anonymous
  • anonymous
i have no idea
anonymous
  • anonymous
Well what did you do to get x alone in \[\large \sf 5x=25\]?
anonymous
  • anonymous
x=5
anonymous
  • anonymous
I know that, but what did you have to do to get that answer?
anonymous
  • anonymous
5 goes into 25 5 times
anonymous
  • anonymous
this test is timed and i dont ahve that much longer i need to stick to this question
anonymous
  • anonymous
\[\large \sf 5x=25 \Rightarrow \frac{5x}{5}=\frac{25}{5} \Rightarrow x=5\]
anonymous
  • anonymous
Since the 5 and x are being multipled together, we divide both sides by 5 to get them apart. This is simple algebra
anonymous
  • anonymous
i need to help with THIS question not x and 25
anonymous
  • anonymous
Well you clearly need some help going over the basics since you don't even know how to solve the current problem.
anonymous
  • anonymous
pls leave if you arent gonna help me solve this question i dont have time for that
anonymous
  • anonymous
Hey buddy, I've been helping this whole time. To be 100% honest it's really irritating trying to help people like you since you clearly haven't been studying since the problem you're asking for is past the things you know how to do. So I'l ask you, do you want my help or not?
anonymous
  • anonymous
if you arent gonna help me get the answer then no i don't
anonymous
  • anonymous
Ok, then I won't ¯\_(ツ)_/¯

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