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anonymous

  • one year ago

Given that the heights and the volumes of the two solids are equivalent, find the diameter of the cylinder. Round your answer to the nearest hundredth

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    A) 2.13mm B) 2.31 mm C) 4.17mm D) 4.27mm

  3. triciaal
    • one year ago
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    |dw:1437511958025:dw|

  4. anonymous
    • one year ago
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    \[\large \sf Volume~of~rectangular~prism\]\[\large \sf V~=~l \times w \times h\] \[\large \sf Volume~of~cylinder\]\[\large \sf V~=~\pi r^{2} h\]

  5. triciaal
    • one year ago
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    diameter is twice the radius, r

  6. anonymous
    • one year ago
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    idk the radius

  7. anonymous
    • one year ago
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    Find the volume of the rectangular prism. Put that volume into the cylinder's formula and solve for the radius.

  8. anonymous
    • one year ago
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    i got 121.635

  9. anonymous
    • one year ago
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    And that's the volume. So now solve for the radius.

  10. anonymous
    • one year ago
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    how do i get the radius

  11. anonymous
    • one year ago
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    \[\large \sf V~=~ \pi r^{2} h\\\large \sf 121.635~=~ \pi r^{2} 8.5\] get r alone

  12. anonymous
    • one year ago
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    I don't know how to get R alone

  13. anonymous
    • one year ago
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    Do you know how to get x alone in \[\large \sf 5x~=~25\]?

  14. anonymous
    • one year ago
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    yes

  15. anonymous
    • one year ago
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    What's different about getting r alone?

  16. anonymous
    • one year ago
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    its harder i dont know how to put it into pie

  17. anonymous
    • one year ago
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    \[\large \sf 121.635~=~r^{2} \times 8.5 \pi\]

  18. anonymous
    • one year ago
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    How about that? Can you get the \(r^{2}\) alone?

  19. anonymous
    • one year ago
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    −∞,∞) {r|r∈R}

  20. anonymous
    • one year ago
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    What?

  21. anonymous
    • one year ago
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    i plugged that into the calculator and thats what i got

  22. anonymous
    • one year ago
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    But that's completely unrelated...

  23. anonymous
    • one year ago
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    i have no idea

  24. anonymous
    • one year ago
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    Well what did you do to get x alone in \[\large \sf 5x=25\]?

  25. anonymous
    • one year ago
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    x=5

  26. anonymous
    • one year ago
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    I know that, but what did you have to do to get that answer?

  27. anonymous
    • one year ago
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    5 goes into 25 5 times

  28. anonymous
    • one year ago
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    this test is timed and i dont ahve that much longer i need to stick to this question

  29. anonymous
    • one year ago
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    \[\large \sf 5x=25 \Rightarrow \frac{5x}{5}=\frac{25}{5} \Rightarrow x=5\]

  30. anonymous
    • one year ago
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    Since the 5 and x are being multipled together, we divide both sides by 5 to get them apart. This is simple algebra

  31. anonymous
    • one year ago
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    i need to help with THIS question not x and 25

  32. anonymous
    • one year ago
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    Well you clearly need some help going over the basics since you don't even know how to solve the current problem.

  33. anonymous
    • one year ago
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    pls leave if you arent gonna help me solve this question i dont have time for that

  34. anonymous
    • one year ago
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    Hey buddy, I've been helping this whole time. To be 100% honest it's really irritating trying to help people like you since you clearly haven't been studying since the problem you're asking for is past the things you know how to do. So I'l ask you, do you want my help or not?

  35. anonymous
    • one year ago
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    if you arent gonna help me get the answer then no i don't

  36. anonymous
    • one year ago
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    Ok, then I won't ¯\_(ツ)_/¯

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