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anonymous

  • one year ago

Create a unique parabola in the pattern f(x) = ax2 + bx + c. Describe the direction of the parabola and determine the y-intercept and zeros.

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  1. anonymous
    • one year ago
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    anyone plz

  2. anonymous
    • one year ago
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    come thru please

  3. campbell_st
    • one year ago
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    well what about a = 1, b = 0 and c = 0

  4. anonymous
    • one year ago
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    can this work

  5. anonymous
    • one year ago
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    2x^2+6x-5

  6. anonymous
    • one year ago
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    @campbell_st

  7. campbell_st
    • one year ago
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    well it can work but the parabola is positive definite, meaning it doesn't have x intercepts.. you could try y = x^2 -6x + 5 that works

  8. anonymous
    • one year ago
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    kk

  9. anonymous
    • one year ago
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    how can i find out the y intercept for x^2 - 6x +5

  10. anonymous
    • one year ago
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    @taramgrant0543664

  11. anonymous
    • one year ago
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    @FlamePlaysMC

  12. taramgrant0543664
    • one year ago
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    To find yintercept you set x as 0

  13. taramgrant0543664
    • one year ago
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    y=(0)^2-6(0)+5 y=?

  14. campbell_st
    • one year ago
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    to find the y-intercept let x = 0 so y = 0 - 0 + 5 so the y-intercept is y = 5 x intercepts let y = 0 so solve \[x^2 - 6x + 5 = 0\] find the factors of 5 that add to -6 both are negative then the factored form of the equation is (x - factor 1)(x - factor 2) = 0 then find the values of x that make each factor equal zero x - factor 1 = 0 x - factor 2 = 0 these values will be the x intercepts

  15. anonymous
    • one year ago
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    Ok so now that I have the y intercept i have to find out the zeros

  16. anonymous
    • one year ago
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    How would i do that

  17. anonymous
    • one year ago
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    @campbell_st

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