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anonymous
 one year ago
Can someone help me walkthrough the problem please???!?!????
anonymous
 one year ago
Can someone help me walkthrough the problem please???!?!????

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0From my understanding of the lesson, I know the since the parabola is opening downwards, I know 'a' is negative

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and a parabola is the graph of a quadratic expression

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0But I do not understand how to find the linear equation, and I don not fully understand how to get an answer for the question

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So what do I do now?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the linear, or the line notice, from the LEFT towards the RIGHT, is really dropping down meaning, is a negative slope anyhow in short, is really x and the quadratic of \(x^2+2\) is also correct for the graph so.... which set do you think it's?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0when x = 1, seems to be the turning point for the graphs if x > 1 the graph is "something" if x < 1 the graph is "something else" what is that "something" and "something else"?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so if it is x>1 the is rising and if the is x<1 the graph is descending?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well... if x > 1, is it rising? x > 1 means, x = 2, x =3, x= 4 ..... is it rising at 2 and 3 and 4 and 5 and so on?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1437519516866:dw
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