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anonymous

  • one year ago

Can someone help me walkthrough the problem please???!?!????

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    From my understanding of the lesson, I know the since the parabola is opening downwards, I know 'a' is negative

  3. jdoe0001
    • one year ago
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    correct

  4. jdoe0001
    • one year ago
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    and a parabola is the graph of a quadratic expression

  5. anonymous
    • one year ago
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    But I do not understand how to find the linear equation, and I don not fully understand how to get an answer for the question

  6. anonymous
    • one year ago
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    So what do I do now?

  7. jdoe0001
    • one year ago
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    the linear, or the line notice, from the LEFT towards the RIGHT, is really dropping down meaning, is a negative slope anyhow in short, is really -x and the quadratic of \(-x^2+2\) is also correct for the graph so.... which set do you think it's?

  8. jdoe0001
    • one year ago
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    when x = 1, seems to be the turning point for the graphs if x > 1 the graph is "something" if x < 1 the graph is "something else" what is that "something" and "something else"?

  9. anonymous
    • one year ago
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    so if it is x>1 the is rising and if the is x<1 the graph is descending?

  10. jdoe0001
    • one year ago
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    well... if x > 1, is it rising? x > 1 means, x = 2, x =3, x= 4 ..... is it rising at 2 and 3 and 4 and 5 and so on?

  11. jdoe0001
    • one year ago
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    |dw:1437519516866:dw|

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spraguer (Moderator)
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