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anonymous
 one year ago
sine of x divided by one minus cosine of x + sine of x divided by one minus cosine of x = 2 csc x
anonymous
 one year ago
sine of x divided by one minus cosine of x + sine of x divided by one minus cosine of x = 2 csc x

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Verify each trigonometric equation by substituting identities to match the right hand side of the equation to the left hand side of the equation.

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0\[\huge\rm \frac{ \sin(x) }{ 1cosine(x) } +\frac{ \sin(x) }{ 1 cosine(x) }\] what is the common denominator ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but the second one is sinx/1+cosx

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0well the common denominator is 1cosine(x) obviously both denominator are same u will get same numerator (sinx)\[\huge\rm \frac{ \sin(x) }{ 1cosine(x) } \]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0huh uhoh are you sure check your question again

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yea i checked it 1+cosx

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0\[\huge\rm \frac{ \sin(x) }{ 1cosine(x) } +\frac{ \sin(x) }{ 1 +cosine(x) }\] so common denominator is (1cosinex)(1+cosinex)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but the picture of the equation in the book says 1+cosx

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0alright you typed it wrong

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it did that itself it copy pasted that way lol

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0really ? :o you didin't type it ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0shocking how that can translate :o :/

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0lol no that was weird tho right?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0\[\huge\rm \frac{ sinx(1+cosx) +sinx(1cosx)}{ (1cosx)(1+cosx)}\] common denominator is (1cosx)(1+cosx) and multiply numerator of first fraction by denominator of 2nd fraction *and multiply numerator of 2nd fraction by denominator of first fraction

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and then you cancel out?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0no no NO! no then u will get the original question

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0yes familiar withe the foil method ? apply that at the denominator

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh okay so i leave the numerator alone righ tnow

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0yep right now distribute both parentheses by sinx 't the numerator

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what? that last sentence you said threw me off i guess the wording did

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0\[\huge\rm \frac{ \color{reD}{sinx}(1+cosx) +\color{red}{sinx}(1cosx)}{ (1cosx)^2}\] distribute both parentheses by red sin x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.01sinx+sinxcosx+1sinxsinxcosx

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0and cos^2x equal to what ? do u remember sin/cos identities ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0special identity \[\huge\rm sin^2x + \cos^2 x = 1\] solve this for cos^2x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0some codes came out for when you said special identity nothing else?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0sin^2x + cos^2x = 1 solve for cos^2 x

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0yes right so replace cos^2x by 1sin^2x

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0\[\huge\rm \frac{ \color{reD}{2sinx}}{ 1(1sin^2x)}\] distribute parentheses by negative one

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0ahh 2sinx over 1(1sin^2x)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry lol im being a pain

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0yes sin^2x is same as sinx times sin x so 2sin over sinx sin x simplfy

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yea but with one over it

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0no what about 2 ? it's 2sinx over sinx times sin x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it all cancels out to 1/sinx

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0no what about 2 ??dw:1437522218631:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im so lost i dont like this number two lol

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0just look at that drawing who kidnapped that 2 ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the sinx? i have no idea

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0sin x cancels out right ?? so where is 2 ? look at there

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0i was about ...to .. put u in jail how....darrrrrrrrrrrrrre u kidnapped 2 :/ ;) hey gtg gO_OD luck!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0haha okay but what do i do to finish?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0well 2 over sinx is same as 2 times 1/sinx and 1/sinx = csc 2 times csc
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