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anonymous

  • one year ago

Judy drove 20 miles from her house to a theater at an average rate of 50 miles per hour. Greg drove from his house to the theater in 1/3 of the time it took Judy to drive to the theater, and they arrived at the same time. If Judy left the house at 7:30 pm, when did Greg leave the house?

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  1. FLVSKidd
    • one year ago
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    speed = distance /time

  2. FLVSKidd
    • one year ago
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    Is it multiple choice?

  3. anonymous
    • one year ago
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    I knew that but go on

  4. anonymous
    • one year ago
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    no

  5. FLVSKidd
    • one year ago
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    I believe it's 7:46pm

  6. anonymous
    • one year ago
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    i need to know how to do it i dont need the answer

  7. FLVSKidd
    • one year ago
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    K so

  8. FLVSKidd
    • one year ago
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    It took judy 24 minutes to get to the theatre and it took greg 1/3 of that.

  9. FLVSKidd
    • one year ago
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    You would divide 24/3 to get 8.

  10. FLVSKidd
    • one year ago
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    If Judy left at 7:30 then she got to the theater 24 minutes later at 7:54. That means Greg had to leave his house at 7:46 in order to arrive at the same time.

  11. FLVSKidd
    • one year ago
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    Because they both left at the same time and greg traveled 1/3 the distance it took Greg 8 minutes to get to the Theatre.

  12. FLVSKidd
    • one year ago
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    I hope that helps.

  13. FLVSKidd
    • one year ago
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    Here:

  14. FLVSKidd
    • one year ago
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    Going at 50mph is would take Judy 24 minutes (2/5 of an hour) to go 20 miles. If Greg got to the theater in 1/3 the time, then that's 8 minutes. If Judy left at 7:30 then she got to the theater 24 minutes later at 7:54. That means Greg had to leave his house at 7:46 in order to arrive at the same time.

  15. FLVSKidd
    • one year ago
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    Do you understand or need more help?

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