anonymous
  • anonymous
find the derivative and second derivative of (x^2-9)^2
Calculus1
katieb
  • katieb
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amoodarya
  • amoodarya
\[y=(x^2-9)^2=\\x^4-18x^2+81\\\]it is easier now to find f',f''
anonymous
  • anonymous
Wouldn't it just be a chain rule from step 1?
amoodarya
  • amoodarya
|dw:1437519674083:dw|

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amoodarya
  • amoodarya
|dw:1437519721063:dw|
anonymous
  • anonymous
That's too confusing lol could you just do the chain rule?
triciaal
  • triciaal
|dw:1437519701313:dw|
anonymous
  • anonymous
Thank you. What about f''(x)?
amoodarya
  • amoodarya
that was chain rule
anonymous
  • anonymous
Sorry amood it was just your hand writing haha no offense
amoodarya
  • amoodarya
what 's f'= ? simplify and writ it here plz
anonymous
  • anonymous
\[4x(x^2-9)\]
triciaal
  • triciaal
|dw:1437519790039:dw|
amoodarya
  • amoodarya
distribute 4x in (x^2-9 ) then take y''
anonymous
  • anonymous
Done, thank you sir Triciaal.
anonymous
  • anonymous
Thanks Amood
triciaal
  • triciaal
@MBilbeisi either way you will get the same result
triciaal
  • triciaal
I am not a Sir
anonymous
  • anonymous
@Triciaal are you good at extreme values?
anonymous
  • anonymous
Sorry, madam.
triciaal
  • triciaal
ok
anonymous
  • anonymous
You are?
triciaal
  • triciaal
maximum and minimum
anonymous
  • anonymous
Yes!!
anonymous
  • anonymous
It's a really hard question i can't seem to get it right
anonymous
  • anonymous
Maybe not so hard for you
triciaal
  • triciaal
when 2nd derivative at critical point is negative you have max when positive then you have minimum
triciaal
  • triciaal
the 2nd derivative is showing the change in the slope the slope is the 1st derivative
anonymous
  • anonymous
So if the question says Find the extreme values of the function and where they occur, i find f'(x) and f''(x)?
triciaal
  • triciaal
out of practice but I had learnt it well enough
anonymous
  • anonymous
\[\left(\begin{matrix}1 \\ x^2-1\end{matrix}\right)\]
triciaal
  • triciaal
find the critical points use in 2nd derivative
triciaal
  • triciaal
sorry have to leave but post question will check back later if still need help
anonymous
  • anonymous
Okay i got you, so for that function i do f', by quotient rule, and then critical values, then f''?
anonymous
  • anonymous
okay i will, thanks
triciaal
  • triciaal
x not = 1 or -1 for this because do not want to divide by 0

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