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anonymous
 one year ago
Find the exact value of cos^(1)(cos(17pi/5))?
anonymous
 one year ago
Find the exact value of cos^(1)(cos(17pi/5))?

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chrisdbest
 one year ago
Best ResponseYou've already chosen the best response.1Can you put that in equation form using the equation button located on the left of the "Post" button?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\cos^{1}(\cos( 17\pi/5))\]

chrisdbest
 one year ago
Best ResponseYou've already chosen the best response.1Based on my calculations, \[\frac{ 3\pi }{ 5 }\]

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1@_alex_urena_ what's the \(cos(\pi)?\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what do you mean @jdoe0001 ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how did you get that @chrisdbest ?

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1ohh, just that... if you were to get the \(cos(\pi)\) what would that give you?

chrisdbest
 one year ago
Best ResponseYou've already chosen the best response.1Sure, I'll tell you

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1ok... so... what is now the \(cos^{1}(1)?\)

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1yeap.... thus... one sec

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1\(\bf cos(\pi )={\color{brown}{ 1}}\qquad cos^{1}({\color{brown}{ 1}})=\pi \\ \quad \\ \textit{thus we could say that }cos^{1}[cos(\pi )]=\pi \\ \quad \\ \textit{thus, we could also say that }cos^{1}\left[ cos\left( \cfrac{17\pi }{5} \right) \right]\implies \cfrac{17\pi }{5}\)

chrisdbest
 one year ago
Best ResponseYou've already chosen the best response.1What he's trying to say is that when you have an inverse cosine and a cosine, they cancel out

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1so in short, \(\bf cos^{1}[cos(whatever)]=whatever\qquad \\ \quad \\sin^{1}[sin(whatever)]=whatever \\ \quad \\ tan^{1}[tan(whatever)]=whatever\)

chrisdbest
 one year ago
Best ResponseYou've already chosen the best response.1Lols, that's basically what I said

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so the answer is 17pi/5 ?

chrisdbest
 one year ago
Best ResponseYou've already chosen the best response.1It might, I thought it was 3pi/5

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1yeap, unless, the inverse function apply, which so far I don't see they do

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1inverse functions restrictions I meant, doesn't seem like in this context they do

chrisdbest
 one year ago
Best ResponseYou've already chosen the best response.1Because the way you wrote it in equation form, I plugged that into my calculator the same way, and I got 3pi/5

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hmmm well how did you get 3pi/5 @chrisdbest

chrisdbest
 one year ago
Best ResponseYou've already chosen the best response.1Because the way you wrote it in equation form, I plugged that into my calculator the same way, and I got 3pi/5

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok but how would you do without the calculator? or do you have to use one to solve this problem?

chrisdbest
 one year ago
Best ResponseYou've already chosen the best response.1I use one to solve the problem.
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