anonymous
  • anonymous
Find the exact value of cos^(-1)(cos(17pi/5))?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
chrisdbest
  • chrisdbest
Can you put that in equation form using the equation button located on the left of the "Post" button?
anonymous
  • anonymous
\[\cos^{-1}(\cos( 17\pi/5))\]
chrisdbest
  • chrisdbest
Aye!

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

chrisdbest
  • chrisdbest
Now that's better!
chrisdbest
  • chrisdbest
Based on my calculations, \[\frac{ 3\pi }{ 5 }\]
jdoe0001
  • jdoe0001
@_alex_urena_ what's the \(cos(\pi)?\)
anonymous
  • anonymous
what do you mean @jdoe0001 ?
anonymous
  • anonymous
how did you get that @chrisdbest ?
jdoe0001
  • jdoe0001
ohh, just that... if you were to get the \(cos(\pi)\) what would that give you?
chrisdbest
  • chrisdbest
Sure, I'll tell you
anonymous
  • anonymous
-1? @jdoe0001
jdoe0001
  • jdoe0001
ok... so... what is now the \(cos^{-1}(-1)?\)
anonymous
  • anonymous
pi
jdoe0001
  • jdoe0001
yeap.... thus... one sec
jdoe0001
  • jdoe0001
\(\bf cos(\pi )={\color{brown}{ -1}}\qquad cos^{-1}({\color{brown}{ -1}})=\pi \\ \quad \\ \textit{thus we could say that }cos^{-1}[cos(\pi )]=\pi \\ \quad \\ \textit{thus, we could also say that }cos^{-1}\left[ cos\left( \cfrac{17\pi }{5} \right) \right]\implies \cfrac{17\pi }{5}\)
chrisdbest
  • chrisdbest
What he's trying to say is that when you have an inverse cosine and a cosine, they cancel out
jdoe0001
  • jdoe0001
so in short, \(\bf cos^{-1}[cos(whatever)]=whatever\qquad \\ \quad \\sin^{-1}[sin(whatever)]=whatever \\ \quad \\ tan^{-1}[tan(whatever)]=whatever\)
chrisdbest
  • chrisdbest
Lols, that's basically what I said
anonymous
  • anonymous
so the answer is 17pi/5 ?
chrisdbest
  • chrisdbest
It might, I thought it was 3pi/5
jdoe0001
  • jdoe0001
yeap, unless, the inverse function apply, which so far I don't see they do
jdoe0001
  • jdoe0001
inverse functions restrictions I meant, doesn't seem like in this context they do
chrisdbest
  • chrisdbest
Because the way you wrote it in equation form, I plugged that into my calculator the same way, and I got 3pi/5
anonymous
  • anonymous
hmmm well how did you get 3pi/5 @chrisdbest
chrisdbest
  • chrisdbest
Because the way you wrote it in equation form, I plugged that into my calculator the same way, and I got 3pi/5
anonymous
  • anonymous
ok but how would you do without the calculator? or do you have to use one to solve this problem?
chrisdbest
  • chrisdbest
I use one to solve the problem.
anonymous
  • anonymous
hmmm ok thnx

Looking for something else?

Not the answer you are looking for? Search for more explanations.