anonymous
  • anonymous
Find the extreme values of the function and where they occur
Calculus1
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
\[1/(x^2-1)\]
anonymous
  • anonymous
@Loser66
Loser66
  • Loser66
What is the definition of extreme value?

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anonymous
  • anonymous
The relative (or local) max/min points.
Loser66
  • Loser66
yes, so that just take derivative of f
anonymous
  • anonymous
Only 1 derivative?
Loser66
  • Loser66
let it =0, find x replace that x into the original function, and you are done.
Loser66
  • Loser66
first derivative only.
anonymous
  • anonymous
Oh! So when i write the answer i just say y=??
Loser66
  • Loser66
When you get the result (x =0) , your conclusion is f(x) has extreme value and x =0 and f(0) = -1
Loser66
  • Loser66
*at, not and f(x) has extreme value AT x =0 ,....
anonymous
  • anonymous
ohh, okay, let me solve it.
anonymous
  • anonymous
\[f'(x)=\left(\begin{matrix}-2x \\ (x^2-1)^2\end{matrix}\right)\]
anonymous
  • anonymous
correct?
Loser66
  • Loser66
It is NOT a matrix, it is a fraction. but it is correct.
anonymous
  • anonymous
yeah sorry, meant to be a fraction
anonymous
  • anonymous
so how do i solve for x from here?
Loser66
  • Loser66
you solve for f' =0 iff the numerator =0
Loser66
  • Loser66
and the numerator is -2x =0 iff x =0, right?
anonymous
  • anonymous
correct
anonymous
  • anonymous
so x=0?
Loser66
  • Loser66
plug back to original one to find value of f(0)=??
anonymous
  • anonymous
-1?
Loser66
  • Loser66
yup
anonymous
  • anonymous
So the answer doesn't have to be like, absolute max = ?? absolute min= ??
anonymous
  • anonymous
sorry just making sure haha
amoodarya
  • amoodarya
|dw:1437521757173:dw|
Loser66
  • Loser66
If you have 2 solutions, plug back and compare which one is larger, the larger one is max, the lesser one is min In this case, you have only 1 solution. You have no comparison, how to say whether it is max or min?
amoodarya
  • amoodarya
|dw:1437521827659:dw| this is sketch of f(X) so x=0 is not abs max
anonymous
  • anonymous
So no absolute max or min?
Loser66
  • Loser66
yup, just local
anonymous
  • anonymous
so is 0 the local max or local min? I'm confused sorry
amoodarya
  • amoodarya
|dw:1437523053515:dw|local max

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