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anonymous

  • one year ago

Did I choose the right answer?

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  1. anonymous
    • one year ago
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  2. dumbcow
    • one year ago
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    incorrect change the radicals to fractional exponents combine exponents by adding/subtracting

  3. jdoe0001
    • one year ago
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    why not just solve it? see what you get

  4. dumbcow
    • one year ago
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    \[\frac{5^{1/3} 5^{1/2}}{5^{5/3}} = \frac{5^{1/3 + 1/2}}{5^{5/3}} = 5^{(1/3)+(1/2) -(5/3)}\]

  5. anonymous
    • one year ago
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    How did you get that 1/2?

  6. jdoe0001
    • one year ago
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    as dumbcow pointed out, \(\large { a^{\frac{{\color{blue} n}}{{\color{red} m}}} \implies \sqrt[{\color{red} m}]{a^{\color{blue} n}} \qquad \qquad \sqrt[{\color{red} m}]{a^{\color{blue} n}}\implies a^{\frac{{\color{blue} n}}{{\color{red} m}}} }\)

  7. anonymous
    • one year ago
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    I get that and I did do that on my paper except why is there a 5 1/2 ? when all there is a is a radical 5

  8. jdoe0001
    • one year ago
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    hmmm those are meant to be exponents

  9. dumbcow
    • one year ago
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    \[\sqrt{a} = \sqrt[2]{a} = a^{1/2}\] for square roots the "2" is left out

  10. anonymous
    • one year ago
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    Is there always a 2 when there is nothing written?

  11. dumbcow
    • one year ago
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    yes

  12. jdoe0001
    • one year ago
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    yap

  13. anonymous
    • one year ago
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    Oh that clears it up real nice then

  14. anonymous
    • one year ago
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    Well than you very much to both of you :) I wish I could give a medal to both of you, but I'll give one to the one with less medals Thanks again!

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spraguer (Moderator)
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