anonymous
  • anonymous
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Mathematics
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
dumbcow
  • dumbcow
incorrect change the radicals to fractional exponents combine exponents by adding/subtracting
jdoe0001
  • jdoe0001
why not just solve it? see what you get

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dumbcow
  • dumbcow
\[\frac{5^{1/3} 5^{1/2}}{5^{5/3}} = \frac{5^{1/3 + 1/2}}{5^{5/3}} = 5^{(1/3)+(1/2) -(5/3)}\]
anonymous
  • anonymous
How did you get that 1/2?
jdoe0001
  • jdoe0001
as dumbcow pointed out, \(\large { a^{\frac{{\color{blue} n}}{{\color{red} m}}} \implies \sqrt[{\color{red} m}]{a^{\color{blue} n}} \qquad \qquad \sqrt[{\color{red} m}]{a^{\color{blue} n}}\implies a^{\frac{{\color{blue} n}}{{\color{red} m}}} }\)
anonymous
  • anonymous
I get that and I did do that on my paper except why is there a 5 1/2 ? when all there is a is a radical 5
jdoe0001
  • jdoe0001
hmmm those are meant to be exponents
dumbcow
  • dumbcow
\[\sqrt{a} = \sqrt[2]{a} = a^{1/2}\] for square roots the "2" is left out
anonymous
  • anonymous
Is there always a 2 when there is nothing written?
dumbcow
  • dumbcow
yes
jdoe0001
  • jdoe0001
yap
anonymous
  • anonymous
Oh that clears it up real nice then
anonymous
  • anonymous
Well than you very much to both of you :) I wish I could give a medal to both of you, but I'll give one to the one with less medals Thanks again!

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