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anonymous
 one year ago
HELP!!!!
Find the foci of 16y^236x^2576=0. Then graph the hyperbole.
anonymous
 one year ago
HELP!!!! Find the foci of 16y^236x^2576=0. Then graph the hyperbole.

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Loser66
 one year ago
Best ResponseYou've already chosen the best response.1move 576 to the right side, what do you get?

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1yes, now, divide both sides by 576, what do you get?

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1\[\dfrac{y^2}{6^2}\dfrac{x^2}{4^2}=1\] right?

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1Hence, its b =6, a =4 ok?

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1foci c, \(c=\sqrt{a^2+b^2}=??\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thanks can you stay with me for just a second i need to write this down

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok is it square root of 52

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1You need know where c is. Your equation has y first, hence its graph is vertical, right? Hence foci will be (0, c) and (0,c) . Yes for c =sqrt 52

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do you put the foci into decimal form for the graph or do you just leave it as c=sqrt52

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay so I would just put the sqrt52 into the graph vertically and be done with the graphing

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay im gonna assume its done
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