anonymous
  • anonymous
Could someone please help me? I'm trying to figure out the problem, but none of the answer choices are what my final answer is coming out to be. Find the angle between the given vectors to the nearest tenth of a degree. u = <2, -4>, v = <3, -8> A. 3.0 Degrees B. 6.0 Degrees C. -7.0 Degrees D. 16.0 Degrees I keep getting around 0.99
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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jim_thompson5910
  • jim_thompson5910
I'm assuming you computed \[\Large \frac{u \cdot v}{|u|*|v|} = 0.9945054529214\] correct?
anonymous
  • anonymous
Yes
jim_thompson5910
  • jim_thompson5910
Apply the arccosine function to both sides to isolate theta \[\Large \cos(\theta) = \frac{u \cdot v}{|u|*|v|}\] \[\Large \cos(\theta) = 0.9945054529214\] \[\Large \arccos(\cos(\theta)) = \arccos(0.9945054529214)\] \[\Large \theta = ???\]

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anonymous
  • anonymous
Oh! So the answer would be 6??
jim_thompson5910
  • jim_thompson5910
yeah arccos(0.9945054529214) = 6.00900595749781

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