anonymous
  • anonymous
***FAN AND MEDAL***
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Sal's Sandwich Shop sells wraps and sandwiches as part of its lunch specials. The profit on every sandwich is $2 and the profit on every wrap is $3. Sal made a profit of $1,470 from lunch specials last month. The equation 2x + 3y = 1,470 represents Sal's profits last month, where x is the number of sandwich lunch specials sold and y is the number of wrap lunch specials sold.
anonymous
  • anonymous
1)Change the equation to slope-intercept form. Identify the slope and y-intercept of the equation. Be sure to show all your work.
anonymous
  • anonymous
2)Describe how you would graph this line using the slope-intercept method. Be sure to write using complete sentences.

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anonymous
  • anonymous
@jim_thompson5910 @mathstudent55 HELP!!!
anonymous
  • anonymous
@ganeshie8 help!!!
anonymous
  • anonymous
Yes
jim_thompson5910
  • jim_thompson5910
did you get #1 started at all?
anonymous
  • anonymous
no
jim_thompson5910
  • jim_thompson5910
they want you to solve 2x + 3y = 1,470 for y. Do you know how?
anonymous
  • anonymous
let me try
jim_thompson5910
  • jim_thompson5910
ok tell me what you get
anonymous
  • anonymous
Part a) 2x + 3y = 1,470 3y = -2x + 1470 y = (-2x + 1470 ) / 3 y = -2/3 * x + 1470/3 y = -2/3 * x + 490 slope is -2/3 y intercept is 490 Part b) Plot the y intercept (0,490) and the x intercept (735,0) Connect the two intercepts with a straight line Part c) f(x) = -2/3 * x + 490 The graph shows the number of wraps sold as a function of the number of sandwiches sold.
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
x = 735-3y/2
anonymous
  • anonymous
Part e) 2x + 3y = 1593 3y = -2x + 1593 y = -2/3*x + 1593/3 y = -2/3*x + 531 The graphs are similar in that they are parallel . They are dissimilar in that they have different y intercepts. Part f) not enough information given. Directions say 'below is a graph'
anonymous
  • anonymous
@jim_thompson5910
anonymous
  • anonymous
hope that helps :)
anonymous
  • anonymous
are you there? @jim_thompson5910 ???
anonymous
  • anonymous
@Kim21 thank you so much!! for the answers

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