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anonymous

  • one year ago

A bowl contains candies of the same size in three flavors: orange, strawberry, and pineapple. If the probability of randomly pulling out an orange candy is fraction 2 over 8, and the probability of randomly pulling out a strawberry candy is fraction 3 over 8, what is the probability of randomly pulling out a pineapple candy?

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  1. anonymous
    • one year ago
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    2/8+3/8 =5/8?

  2. anonymous
    • one year ago
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    2/8-3/8 = 1/8?

  3. anonymous
    • one year ago
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    64% is what i got and ill show you how...

  4. anonymous
    • one year ago
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    ok

  5. anonymous
    • one year ago
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    We need to end up with \(\Large\rm \frac{8}{8}\) with our three individual odds.

  6. anonymous
    • one year ago
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    So far we have \(\Large\rm \frac{2}{8}\) and \(\Large\rm \frac{3}{8}\)

  7. anonymous
    • one year ago
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    o then the pineapple would be 3/8

  8. anonymous
    • one year ago
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    since they should be equal?

  9. anonymous
    • one year ago
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    so im sorry i meant 3/8 not 64%-i dont know where that came from :b

  10. anonymous
    • one year ago
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    yes! :)

  11. anonymous
    • one year ago
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    thanks @Kim21 got it

  12. anonymous
    • one year ago
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    welcome :)

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