anonymous
  • anonymous
A bowl contains candies of the same size in three flavors: orange, strawberry, and pineapple. If the probability of randomly pulling out an orange candy is fraction 2 over 8, and the probability of randomly pulling out a strawberry candy is fraction 3 over 8, what is the probability of randomly pulling out a pineapple candy?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
2/8+3/8 =5/8?
anonymous
  • anonymous
2/8-3/8 = 1/8?
anonymous
  • anonymous
64% is what i got and ill show you how...

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anonymous
  • anonymous
ok
anonymous
  • anonymous
We need to end up with \(\Large\rm \frac{8}{8}\) with our three individual odds.
anonymous
  • anonymous
So far we have \(\Large\rm \frac{2}{8}\) and \(\Large\rm \frac{3}{8}\)
anonymous
  • anonymous
o then the pineapple would be 3/8
anonymous
  • anonymous
since they should be equal?
anonymous
  • anonymous
so im sorry i meant 3/8 not 64%-i dont know where that came from :b
anonymous
  • anonymous
yes! :)
anonymous
  • anonymous
thanks @Kim21 got it
anonymous
  • anonymous
welcome :)

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