A bowl contains candies of the same size in three flavors: orange, strawberry, and pineapple. If the probability of randomly pulling out an orange candy is fraction 2 over 8, and the probability of randomly pulling out a strawberry candy is fraction 3 over 8, what is the probability of randomly pulling out a pineapple candy?

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A bowl contains candies of the same size in three flavors: orange, strawberry, and pineapple. If the probability of randomly pulling out an orange candy is fraction 2 over 8, and the probability of randomly pulling out a strawberry candy is fraction 3 over 8, what is the probability of randomly pulling out a pineapple candy?

Mathematics
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2/8+3/8 =5/8?
2/8-3/8 = 1/8?
64% is what i got and ill show you how...

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Other answers:

ok
We need to end up with \(\Large\rm \frac{8}{8}\) with our three individual odds.
So far we have \(\Large\rm \frac{2}{8}\) and \(\Large\rm \frac{3}{8}\)
o then the pineapple would be 3/8
since they should be equal?
so im sorry i meant 3/8 not 64%-i dont know where that came from :b
yes! :)
thanks @Kim21 got it
welcome :)

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