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anonymous
 one year ago
PreCal help
anonymous
 one year ago
PreCal help

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0When f(x) becomes f(x)  1: This is a vertical shift that moves the function down by 1. Therefore, the yintercept also moves down by 1. Nothing else is affected because you simply nudged it downwards. When f(x) becomes f(x) + 1 Again, the vertical shift here only nudges it. However, it's also multiplied by 1, which reflects the entire function over the xaxis because anything that was positive becomes negative and vice versa. This end behavior changes the same way; if it went up on one side, it'll now go down instead and vice versa.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So what regions would be increasing/decreasing?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well...Basically for f(x) + 2 the yintercept moves up two units For (1/2)*f(x) the yintercept flips to negative if it was positive and to positive it was negative.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok! That makes sense. I'm not getting the end behavior thing though

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok so how about this let me reexplain it for you :) ...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0f(x)+2 is a translation +2 in the direction of the yaxis (i.e. upwards) 1/2f(x), the graph get turned upside down, so times all the y coordinates by 1. The y coordinates will also be multiplied by a 1/2. So basically multiply all your y coordinates by a 1/2
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