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anonymous

  • one year ago

Pre-Cal help

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  1. anonymous
    • one year ago
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    When f(x) becomes f(x) - 1: This is a vertical shift that moves the function down by 1. Therefore, the y-intercept also moves down by 1. Nothing else is affected because you simply nudged it downwards. When f(x) becomes -f(x) + 1 Again, the vertical shift here only nudges it. However, it's also multiplied by -1, which reflects the entire function over the x-axis because anything that was positive becomes negative and vice versa. This end behavior changes the same way; if it went up on one side, it'll now go down instead and vice versa.

  2. anonymous
    • one year ago
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    @Raindropssss

  3. anonymous
    • one year ago
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    @kim21 yes

  4. anonymous
    • one year ago
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    So what regions would be increasing/decreasing?

  5. anonymous
    • one year ago
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    well...Basically for f(x) + 2 the y-intercept moves up two units For (-1/2)*f(x) the y-intercept flips to negative if it was positive and to positive it was negative.

  6. anonymous
    • one year ago
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    ok! That makes sense. I'm not getting the end behavior thing though

  7. anonymous
    • one year ago
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    ok so how about this let me re-explain it for you :) ...

  8. anonymous
    • one year ago
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    f(x)+2 is a translation +2 in the direction of the y-axis (i.e. upwards) -1/2f(x), the graph get turned upside down, so times all the y co-ordinates by -1. The y coordinates will also be multiplied by a 1/2. So basically multiply all your y coordinates by a 1/2

  9. anonymous
    • one year ago
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    Thanks!!

  10. anonymous
    • one year ago
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    welcome :)

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