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anonymous

  • one year ago

The work of a student to find the dimensions of a rectangle of area 8 + 16x and width 4 is shown below: Step 1: 8 + 16x Step 2: 4(4) + 4(12x) Step 3: 4(4 + 12x) Step 4: Dimensions of the rectangle are 4 and 4 + 12x In which step did the student first make an error and what is the correct step? Step 3; 4 + (4 + 12x) Step 3; 4 + (4 ⋅ 12x) Step 2; 4(2) + 4(4x) Step 2; 4(2) + 4x(2)

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  1. anonymous
    • one year ago
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    @dan815

  2. anonymous
    • one year ago
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    @DecentNabeel

  3. calculusxy
    • one year ago
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    To find the area of a rectangle what you do is: length x width = area You already have the width as 4 and area: length x 4 = 8 + 16x \[l \times 4 = 8 + 16x\] To solve for l (length) you need to isolate and use the division property of equality: \[\frac{ l \times 4 }{ 4 } = \frac{ 8 + 16x }{ 4 }\] Clearly the student did the inverse in one of the steps. Can you find out which step he/she did that?

  4. anonymous
    • one year ago
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    C Step 2; 4(2) + 4(4x)

  5. calculusxy
    • one year ago
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    Yes

  6. anonymous
    • one year ago
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    Yay c:

  7. calculusxy
    • one year ago
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    Great job!

  8. anonymous
    • one year ago
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    Thanks for your help (:

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