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zmudz
 one year ago
For what value \(k\) is the following function continuous at \(x=2\)?
\(f(x) = \begin{cases}
\frac{\sqrt{2x+5}\sqrt{x+7}}{x2} & x \neq 2 \\
k & x = 2
\end{cases}\)
zmudz
 one year ago
For what value \(k\) is the following function continuous at \(x=2\)? \(f(x) = \begin{cases} \frac{\sqrt{2x+5}\sqrt{x+7}}{x2} & x \neq 2 \\ k & x = 2 \end{cases}\)

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You could approach this using limits, or you could 1) Evaluate f(x) for x just larger than 2, say 2.001 2) Evaluate f(x) for x just less than 2, say 1.999 3) Choose the value between these two.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You might even be able to graph the function and determine the limit at x=2.

ali2x2
 one year ago
Best ResponseYou've already chosen the best response.0ospreytriple makes me look like dirt >:o
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