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zmudz

  • one year ago

For what value \(k\) is the following function continuous at \(x=2\)? \(f(x) = \begin{cases} \frac{\sqrt{2x+5}-\sqrt{x+7}}{x-2} & x \neq 2 \\ k & x = 2 \end{cases}\)

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  1. ali2x2
    • one year ago
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  2. anonymous
    • one year ago
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    You could approach this using limits, or you could 1) Evaluate f(x) for x just larger than 2, say 2.001 2) Evaluate f(x) for x just less than 2, say 1.999 3) Choose the value between these two.

  3. anonymous
    • one year ago
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    You might even be able to graph the function and determine the limit at x=2.

  4. ali2x2
    • one year ago
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    ospreytriple makes me look like dirt >:o

  5. ali2x2
    • one year ago
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    :P

  6. ali2x2
    • one year ago
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    nahhhh

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