anonymous
  • anonymous
Find the standard form of the equation of the parabola with a focus at (-2, 0) and a directrix at x = 2.
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
(y - 0)^2 = 4(-2)(x - 0)?? P not equal to -2?
anonymous
  • anonymous
assume a point on parabola p(x,y)
anonymous
  • anonymous
let s be the focus with co ordinates (-2,0) and M be the point on the directrix

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anonymous
  • anonymous
|dw:1437545577368:dw|
anonymous
  • anonymous
|dw:1437545695275:dw|
anonymous
  • anonymous
now find the length of PM .
anonymous
  • anonymous
and the length of PS
anonymous
  • anonymous
PS=PM equade it u will get the equation of parabola
anonymous
  • anonymous
the length of PS can be found out by using the distance formula
anonymous
  • anonymous
4?
anonymous
  • anonymous
|dw:1437545924499:dw|
anonymous
  • anonymous
what 4 ?
anonymous
  • anonymous
I don't get it
anonymous
  • anonymous
Aren't I supposed to be using the parabola formulas
anonymous
  • anonymous
this is a way to find the eq of parabola which can be reduced to its general form i.e. y^2 =4ax
anonymous
  • anonymous
ur username isnt valid i cant send u msg
anonymous
  • anonymous
uhh what do I do with y^2 = 4ax
anonymous
  • anonymous
its a general form of equation of parabola
anonymous
  • anonymous
can I use focus (h, k + p) directrix y = k - p (x - h)2 = 4p(y - k)
anonymous
  • anonymous
can u solve the equation i told to u
anonymous
  • anonymous
yes u can .
anonymous
  • anonymous
I've never used that y^2=4ax thing I don't know what to put in
anonymous
  • anonymous
is it y^2 = -8x

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