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anonymous

  • one year ago

Find the standard form of the equation of the parabola with a focus at (-2, 0) and a directrix at x = 2.

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  1. anonymous
    • one year ago
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    (y - 0)^2 = 4(-2)(x - 0)?? P not equal to -2?

  2. anonymous
    • one year ago
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    assume a point on parabola p(x,y)

  3. anonymous
    • one year ago
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    let s be the focus with co ordinates (-2,0) and M be the point on the directrix

  4. anonymous
    • one year ago
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    |dw:1437545577368:dw|

  5. anonymous
    • one year ago
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    |dw:1437545695275:dw|

  6. anonymous
    • one year ago
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    now find the length of PM .

  7. anonymous
    • one year ago
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    and the length of PS

  8. anonymous
    • one year ago
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    PS=PM equade it u will get the equation of parabola

  9. anonymous
    • one year ago
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    the length of PS can be found out by using the distance formula

  10. anonymous
    • one year ago
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    4?

  11. anonymous
    • one year ago
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    |dw:1437545924499:dw|

  12. anonymous
    • one year ago
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    what 4 ?

  13. anonymous
    • one year ago
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    I don't get it

  14. anonymous
    • one year ago
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    Aren't I supposed to be using the parabola formulas

  15. anonymous
    • one year ago
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    this is a way to find the eq of parabola which can be reduced to its general form i.e. y^2 =4ax

  16. anonymous
    • one year ago
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    ur username isnt valid i cant send u msg

  17. anonymous
    • one year ago
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    uhh what do I do with y^2 = 4ax

  18. anonymous
    • one year ago
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    its a general form of equation of parabola

  19. anonymous
    • one year ago
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    can I use focus (h, k + p) directrix y = k - p (x - h)2 = 4p(y - k)

  20. anonymous
    • one year ago
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    can u solve the equation i told to u

  21. anonymous
    • one year ago
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    yes u can .

  22. anonymous
    • one year ago
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    I've never used that y^2=4ax thing I don't know what to put in

  23. anonymous
    • one year ago
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    is it y^2 = -8x

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spraguer (Moderator)
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