is it -x^2 ?
are there options ?
I know how to graph it, I just don't know how to explain it
is my graph same a urs ?
yes its same
dont mind drawing though :P
u know how to draw graph of x^2 ?
Yea, but I mean I don't know how to write it down so it sounds better
it syas that for x>1 u need to draw the graph of y=x and for x<1 u need to draw the graph of y=-x^2
it says give directions on how to draw the graph
\[y = -x^2 .................x <1 \] \[y = x .................x >1 \] We are given a piece wise function. For x > 1 we draw y = x we let x be any number we choose. (it's just a straight line. ex. if x = 1 then y = 1 and (1,1) will be your point. For x < 1 we draw \[y=-x^2\] and again we just let x be any number we choose like for example if x = 1. Then \[y=-1^2=-1\] \[y=-x^2 \] is a reflection of the regular parabola which is \[y=x^2 \]
hold on .. for > < signs we have an open circle. Your problem does have just < and > signs right?
the graph is correct but for that y = x on the desmos attachment. There should be an open circle.