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anonymous

  • one year ago

Which of the following could be the ratio between the lengths of the two legs of a 30-60-90 triangle? http://i1378.photobucket.com/albums/ah115/tonianncampbell9/Problem_zpsjf8fpccc.png

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  1. aric200
    • one year ago
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    I Believe it is C hold on

  2. aric200
    • one year ago
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    Actually I believe it is A can you only have one answer?

  3. anonymous
    • one year ago
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    i chose those answers but it was incorrect, thats why i needed help @aric200

  4. aric200
    • one year ago
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    What did you choose?

  5. anonymous
    • one year ago
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    i chose a and c

  6. aric200
    • one year ago
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    I said hold On I was checking but I was not sure. I was trying to let you know I'm working on it and to be patient but if you got it wrong it was not because of me

  7. anonymous
    • one year ago
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    lol i know i did the problem before hand and i got the same answers you thought of @aric200

  8. aric200
    • one year ago
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    Oh Alright I thought you were blaming it on me.. awkward.

  9. aric200
    • one year ago
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    Maybe it was just A because C is iffy

  10. aric200
    • one year ago
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    http://www.regentsprep.org/regents/math/algtrig/att2/ltri30.htm

  11. aric200
    • one year ago
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    I know A for sure just dont know about any others

  12. anonymous
    • one year ago
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    yea that was one of my choices but i've came to the conclusion that it has to be 3 answers there

  13. anonymous
    • one year ago
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    @UsukiDoll @Elsa213 @AG23 Can you help me with this question?

  14. welshfella
    • one year ago
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    A is definitely one

  15. welshfella
    • one year ago
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    |dw:1437558636771:dw|

  16. phi
    • one year ago
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    you are looking for the ratio "short leg" / "long leg" to be 1/ sqr(3) (the legs are the two sides that are not the hypotenuse) choice A show 1/sqr(3) so that is an answer B simplifies to 1 , which is not the same as 1/sqr(3). ditto E. choice C: \[ \frac{\sqrt{2} }{\sqrt{3}}=? \frac{1}{\sqrt{3}} \] if you multiply both sides by sqr(3) you get \( \sqrt{2}=? 1\) no, sqr(2) is bigger than 1 choice D \[ \frac{1}{\sqrt{2}} =? \frac{1}{\sqrt{3}} \] if you square each side , you get \( \frac{1}{2}=?\frac{1}{3} \) clearly not true. choice E, =1 , so no choice F: \[ \frac{ 2 \sqrt{3}}{6} =?\frac{1}{\sqrt{3} }\] simplify 2/6 to 1/3 \[ \frac{ \sqrt{3}}{3} =?\frac{1}{\sqrt{3} }\] if we square both sides we get \( \frac{3}{9}= ? \frac{1}{3} \) yes, 3/9 = 1/3. so choice F works.

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