Which of the following could be the ratio between the lengths of the two legs of a 30-60-90 triangle?
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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- anonymous

- jamiebookeater

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- aric200

I Believe it is C hold on

- aric200

Actually I believe it is A can you only have one answer?

- anonymous

i chose those answers but it was incorrect, thats why i needed help @aric200

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## More answers

- aric200

What did you choose?

- anonymous

i chose a and c

- aric200

I said hold On I was checking but I was not sure. I was trying to let you know I'm working on it and to be patient but if you got it wrong it was not because of me

- anonymous

lol i know i did the problem before hand and i got the same answers you thought of @aric200

- aric200

Oh Alright I thought you were blaming it on me.. awkward.

- aric200

Maybe it was just A because C is iffy

- aric200

http://www.regentsprep.org/regents/math/algtrig/att2/ltri30.htm

- aric200

I know A for sure just dont know about any others

- anonymous

yea that was one of my choices but i've came to the conclusion that it has to be 3 answers there

- anonymous

- welshfella

A is definitely one

- welshfella

|dw:1437558636771:dw|

- phi

you are looking for the ratio "short leg" / "long leg" to be 1/ sqr(3)
(the legs are the two sides that are not the hypotenuse)
choice A show 1/sqr(3) so that is an answer
B simplifies to 1 , which is not the same as 1/sqr(3). ditto E.
choice C:
\[ \frac{\sqrt{2} }{\sqrt{3}}=? \frac{1}{\sqrt{3}} \]
if you multiply both sides by sqr(3) you get \( \sqrt{2}=? 1\)
no, sqr(2) is bigger than 1
choice D
\[ \frac{1}{\sqrt{2}} =? \frac{1}{\sqrt{3}} \]
if you square each side , you get \( \frac{1}{2}=?\frac{1}{3} \)
clearly not true.
choice E, =1 , so no
choice F: \[ \frac{ 2 \sqrt{3}}{6} =?\frac{1}{\sqrt{3} }\]
simplify 2/6 to 1/3
\[ \frac{ \sqrt{3}}{3} =?\frac{1}{\sqrt{3} }\]
if we square both sides we get \( \frac{3}{9}= ? \frac{1}{3} \)
yes, 3/9 = 1/3. so choice F works.

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