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anonymous
 one year ago
Select whether the equation has a solution or not. Explain every step pls
anonymous
 one year ago
Select whether the equation has a solution or not. Explain every step pls

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\sqrt{x}+1=72\sqrt{x}\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1let's try find our x...

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1so there's a variable on the right. add to both sides to shift it to the left and then subtract 1 on both sides.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok so now we have\[\sqrt{x}=62\sqrt{x}\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1ok good so far... what next? we want all variables to the left...

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1yay... now divide both sides

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh ok that was actually pretty easy x=4 I just messed up really early and it got complicated from there. Thanks

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So yeah it has a solution

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1you can plug 4 into the original equation to see if it equals.. I'm sure it does XD

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1when you plugged x = 4 back into the original equation, did you get 3?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1how though? \[\sqrt{4}+1=72\sqrt{4}\] \[2+1=72(2)\] \[3=74\] \[3=3\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh well I didn't use the original equation I started when we had already subtracted 1 from each side but I see how u did it the original way too

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1to check to see if the solution works.. plug it back into the original equation... but I guess plugging it back earlier would work too... but it's best to do this to the original equation
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