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anonymous

  • one year ago

Select whether the equation has a solution or not. Explain every step pls

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  1. anonymous
    • one year ago
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    \[\sqrt{x}+1=7-2\sqrt{x}\]

  2. UsukiDoll
    • one year ago
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    let's try find our x...

  3. UsukiDoll
    • one year ago
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    so there's a variable on the right. add to both sides to shift it to the left and then subtract 1 on both sides.

  4. UsukiDoll
    • one year ago
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    @MrNood is back! :D

  5. anonymous
    • one year ago
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    ok so now we have\[\sqrt{x}=6-2\sqrt{x}\]

  6. UsukiDoll
    • one year ago
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    ok good so far... what next? we want all variables to the left...

  7. anonymous
    • one year ago
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    \[3\sqrt{x}=6\]

  8. UsukiDoll
    • one year ago
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    yay... now divide both sides

  9. UsukiDoll
    • one year ago
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    the number parts

  10. anonymous
    • one year ago
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    Oh ok that was actually pretty easy x=4 I just messed up really early and it got complicated from there. Thanks

  11. anonymous
    • one year ago
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    So yeah it has a solution

  12. UsukiDoll
    • one year ago
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    you can plug 4 into the original equation to see if it equals.. I'm sure it does XD

  13. UsukiDoll
    • one year ago
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    when you plugged x = 4 back into the original equation, did you get 3?

  14. anonymous
    • one year ago
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    I got 2=2

  15. UsukiDoll
    • one year ago
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    how though? \[\sqrt{4}+1=7-2\sqrt{4}\] \[2+1=7-2(2)\] \[3=7-4\] \[3=3\]

  16. anonymous
    • one year ago
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    Oh well I didn't use the original equation I started when we had already subtracted 1 from each side but I see how u did it the original way too

  17. UsukiDoll
    • one year ago
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    to check to see if the solution works.. plug it back into the original equation... but I guess plugging it back earlier would work too... but it's best to do this to the original equation

  18. anonymous
    • one year ago
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    ok thanks

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