Select whether the equation has a solution or not. Explain every step pls

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Select whether the equation has a solution or not. Explain every step pls

Mathematics
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\[\sqrt{x}+1=7-2\sqrt{x}\]
let's try find our x...
so there's a variable on the right. add to both sides to shift it to the left and then subtract 1 on both sides.

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@MrNood is back! :D
ok so now we have\[\sqrt{x}=6-2\sqrt{x}\]
ok good so far... what next? we want all variables to the left...
\[3\sqrt{x}=6\]
yay... now divide both sides
the number parts
Oh ok that was actually pretty easy x=4 I just messed up really early and it got complicated from there. Thanks
So yeah it has a solution
you can plug 4 into the original equation to see if it equals.. I'm sure it does XD
when you plugged x = 4 back into the original equation, did you get 3?
I got 2=2
how though? \[\sqrt{4}+1=7-2\sqrt{4}\] \[2+1=7-2(2)\] \[3=7-4\] \[3=3\]
Oh well I didn't use the original equation I started when we had already subtracted 1 from each side but I see how u did it the original way too
to check to see if the solution works.. plug it back into the original equation... but I guess plugging it back earlier would work too... but it's best to do this to the original equation
ok thanks

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