Radical Equation help?

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Radical Equation help?

Mathematics
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If I end up stalling in the middle, it means my batteries in my wireless mouse are dead and I need to replace them
Select whether the equation has a solution or not. \[\sqrt[3]{x-5}-2=0\]
Ok

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ok so remember that we need all variable need to be on the left that 2 needs to go on the right.
Ok so its gonna be the radical thing = 2
yeah that cube root =2
\[\large \sqrt[3]{x-5}=2\]
x-5=8
so now to get rid of that cube root... blah let's just rearra...........you've taken ^3 on both sides... impressive.. ok.. now solve for x
Ok so x=13 that wasn't so hard I just wasn't sure since that little number 3 is new to me even though i know what it means
that means cube root
plug x = 13 back into the equation and see what happens (doesn't have to be the original equation this time)
Ok I got 8=8 and 0=0 depending on how you put it in
that indicates that you've done the problem correctly
ok cool thanks
guess this was solved. don't hate on math :)
I'll try lol

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