## anonymous one year ago MEDAL AND FAN What are the vertical asymptotes of the function f(x) = the quantity of 4 x plus 8, all over x squared plus 3 x minus 4

1. anonymous

i think x=-1 and x=2

2. anonymous

does anyone know if i am right

3. UsukiDoll

$f(x) = \frac{4x+8}{x^2+3x-4}$

4. UsukiDoll

5. UsukiDoll

I'm gonna assume it is. Anyway , Vertical asymptotes are vertical lines which correspond to the zeroes of the denominator of a rational function. so we have to factor $x^2+3x-4$

6. UsukiDoll

$(x+1)(x-4) = 0$ solve for x x+1 = 0 and x-4 = 0 only x = -1 is correct so try solving x-4=0

7. anonymous

4

8. UsukiDoll

yup x = 4, and x = -1 are our vertical asymptotes good job :)