x + y = 3k x - y = k The solution of the system shown is _____. (0, 2k) (2k, 0) (2k, k)

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x + y = 3k x - y = k The solution of the system shown is _____. (0, 2k) (2k, 0) (2k, k)

Algebra
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use elimination method
Add those 2 equations and y will be eliminated and you get the value of x. Substitute the value of x in any equation and find y. Once you get the value of x and y, then the solution will be of the form (x , y)
but what is the answer

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Other answers:

am so sorry..... i cant provide the answer...
no direct answer ing allowed... but we can guide you :) first add the two equations together. Noticed that a variable will cancel out
why i really need it
because giving a direct answer is against code of conduct and mods will be issuing warnings. that's what.
mmm okay thanks so how i can do that again
x+y =3k x-y=k add them together.
3k=k
no... |dw:1437569730364:dw|
it wiil be llike that x2-y2
the y's should cancel out
|dw:1437569843258:dw|
i don't get it
Look at the y. One y is +y and the other y is -y y - y = 0 so we get ride of the y \( x = 3k \) \( x = k \) Now add those
x + x + ?? and 3k + k = ??
That was x + x = ???
2k,k
x + x = 2x 3k + k = 4k Now we have \(x = 3k \) \(x= k \) \( 2x = 4k\) Now divide by 2 and what do you get for x?
Yes, (2k,k) is the answer
|dw:1437570395517:dw| then plug x = 2k back into the equation (one of them) |dw:1437570428355:dw| so x = 2k and y = k (2k,k)

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