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anonymous

  • one year ago

x + y = 3k x - y = k The solution of the system shown is _____. (0, 2k) (2k, 0) (2k, k)

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  1. UsukiDoll
    • one year ago
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    use elimination method

  2. midhun.madhu1987
    • one year ago
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    Add those 2 equations and y will be eliminated and you get the value of x. Substitute the value of x in any equation and find y. Once you get the value of x and y, then the solution will be of the form (x , y)

  3. anonymous
    • one year ago
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    but what is the answer

  4. midhun.madhu1987
    • one year ago
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    am so sorry..... i cant provide the answer...

  5. UsukiDoll
    • one year ago
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    no direct answer ing allowed... but we can guide you :) first add the two equations together. Noticed that a variable will cancel out

  6. anonymous
    • one year ago
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    why i really need it

  7. UsukiDoll
    • one year ago
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    because giving a direct answer is against code of conduct and mods will be issuing warnings. that's what.

  8. anonymous
    • one year ago
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    mmm okay thanks so how i can do that again

  9. UsukiDoll
    • one year ago
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    x+y =3k x-y=k add them together.

  10. anonymous
    • one year ago
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    3k=k

  11. UsukiDoll
    • one year ago
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    no... |dw:1437569730364:dw|

  12. anonymous
    • one year ago
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    it wiil be llike that x2-y2

  13. UsukiDoll
    • one year ago
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    the y's should cancel out

  14. UsukiDoll
    • one year ago
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    |dw:1437569843258:dw|

  15. anonymous
    • one year ago
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    i don't get it

  16. anonymous
    • one year ago
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    Look at the y. One y is +y and the other y is -y y - y = 0 so we get ride of the y \( x = 3k \) \( x = k \) Now add those

  17. anonymous
    • one year ago
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    x + x + ?? and 3k + k = ??

  18. anonymous
    • one year ago
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    That was x + x = ???

  19. anonymous
    • one year ago
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    2k,k

  20. anonymous
    • one year ago
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    x + x = 2x 3k + k = 4k Now we have \(x = 3k \) \(x= k \) \( 2x = 4k\) Now divide by 2 and what do you get for x?

  21. anonymous
    • one year ago
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    Yes, (2k,k) is the answer

  22. UsukiDoll
    • one year ago
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    |dw:1437570395517:dw| then plug x = 2k back into the equation (one of them) |dw:1437570428355:dw| so x = 2k and y = k (2k,k)

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