WILL MEDAL AND FAN!!! Express answer in exact form. Find the area of the larger segment whose chord is 8" long in a circle with an 8" radius. (Hint: A chord divides a circle into two segments. In problem 1, you found the area of the smaller segment.) and is there any way to put the answer in this format? https://suwannee.owschools.com/media/g_geo_2013/8/q255_x.gif

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WILL MEDAL AND FAN!!! Express answer in exact form. Find the area of the larger segment whose chord is 8" long in a circle with an 8" radius. (Hint: A chord divides a circle into two segments. In problem 1, you found the area of the smaller segment.) and is there any way to put the answer in this format? https://suwannee.owschools.com/media/g_geo_2013/8/q255_x.gif

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Other answers:

yeah
dO YOU KNOW WHAT TO DO?
i think so hold up
We know that the triangle formed by the two radii and the chord is an equilateral triangle, all angles are 60 degrees, which is 1/6 of 360 degrees : Find area inside the 60 degree arc 1/6*pi*8= 35.51 : Find the area of the equilateral triangle 1/2*8*SQRT8^2-4^2 = 27.71 sq/in : Find the area of the shape enclosed by the 60 degree arc and the chord 35.51 - 27.71 = 7.8 sq/in : Find the area of the larger segment pi*8^2 - 7.8 = 193.26 sq/inches
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That's kinda what the picture looks like. It wants me to find the area of the part that's shaded in
The radius of the circle is 8inches and so is the chord
Find area inside the 60 degree arc
The arc is 60degrees?
How's that possible?
Just curious
no look at the paragrph i just showed u
Graph?
I don't see one
no
Oh. sry MB
But still, what does a triangle come in
We know that the triangle formed by the two radii and the chord is an equilateral triangle, all angles are 60 degrees, which is 1/6 of 360 degrees :
Omg. Idk what, but something just clicked inside my head. Oh wow, now I feel so stupid jeez...
man stated from the bottem video is still funny
?
started from the bottom video its funny
What video?
gtg sorry
Usually about this time every day huh?

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