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If \(x,y \in [0, \pi/2)\):\[\sin^4 x + \cos^4 y + 2 = 4\sin x \cos y\]Then find the value of:\[\sin x + \sin y \]... The answer is given as 2.
I have two issues with this: one, \(\pi/2\) is not included. If I acknowledge this as a small mistake, even then, if \(\sin x + \sin y = 2\), then \(x = y = \pi/2\). But of course this does not satisfy the condition. Here is what *does* satisfy the condition: \(x = 0;~ y = \pi/2\)
@oldrin.bataku of course.
Oops, I meant that \(y = 0; x = \pi/2\) satisfies the condition. Moving on...
Pi/2 MUST be included.
I've solved the question thoroughly nd m sure that pi/2 mst be included.
Even then, the answer couldn't be 2, right?
Also, how did you solve this question thoroughly if you don't mind explaining?
K wait lemme switch on my laptop :)
Did you solve this my maxima-minima or ...?
No i jst simplified the expression
Yeah, that's what I got too... finally.
So the answer isn't 2, it's 1, right?
The question asked for sin x + sin y...
yes its one :)
Cool, I was wondering where the mistake was in my work. There wasn't any. I'll report this, thanks!
ur welcome :)