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ParthKohli
 one year ago
I will state the question exactly as it is:
ParthKohli
 one year ago
I will state the question exactly as it is:

This Question is Closed

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1If \(x,y \in [0, \pi/2)\):\[\sin^4 x + \cos^4 y + 2 = 4\sin x \cos y\]Then find the value of:\[\sin x + \sin y \]... The answer is given as 2.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Mehek14 @pinkbubbles

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1I have two issues with this: one, \(\pi/2\) is not included. If I acknowledge this as a small mistake, even then, if \(\sin x + \sin y = 2\), then \(x = y = \pi/2\). But of course this does not satisfy the condition. Here is what *does* satisfy the condition: \(x = 0;~ y = \pi/2\)

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1@oldrin.bataku of course.

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1Oops, I meant that \(y = 0; x = \pi/2\) satisfies the condition. Moving on...

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.8Pi/2 MUST be included.

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.8I've solved the question thoroughly nd m sure that pi/2 mst be included.

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1Even then, the answer couldn't be 2, right?

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1Also, how did you solve this question thoroughly if you don't mind explaining?

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.8K wait lemme switch on my laptop :)

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1Did you solve this my maximaminima or ...?

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.8No i jst simplified the expression

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1Yeah, that's what I got too... finally.

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1So the answer isn't 2, it's 1, right?

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1The question asked for sin x + sin y...

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1Cool, I was wondering where the mistake was in my work. There wasn't any. I'll report this, thanks!
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