anonymous
  • anonymous
fan medal and testimony help!!!. What is the solution to the equation 1.2m − 0.8 = −2.0m? m = 0.25 m = 0.4 m = 1 m = 4
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Mehek14
  • Mehek14
first add 1.2 + 2
anonymous
  • anonymous
3.2
Mehek14
  • Mehek14
and add 0 + 0.8

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More answers

anonymous
  • anonymous
0.8
Mehek14
  • Mehek14
so you have \(3.2m = 0.8\) now divide \(\dfrac{0.8}{3.2}\)
anonymous
  • anonymous
0.25
Mehek14
  • Mehek14
\(m=0.25\)
anonymous
  • anonymous
thanks can you help with a couple more
Mehek14
  • Mehek14
sure
anonymous
  • anonymous
thanks your great!
Mehek14
  • Mehek14
^_^
anonymous
  • anonymous
Which statement is true about the equation fraction 3 over 4z − fraction 1 over 4z + 1 = fraction 2 over 4z + 1? It has no solution. It has one solution. It has two solutions. It has infinitely many solutions.
anonymous
  • anonymous
DO YOU KNOW HOW TO
anonymous
  • anonymous
oops cap lock sorry
Mehek14
  • Mehek14
\(\dfrac{3}{4z}-\dfrac{1}{4z+1}=\dfrac{2}{4z+1}\)
Mehek14
  • Mehek14
\(\dfrac{3}{4z}=\dfrac{3}{4z+1}\)
anonymous
  • anonymous
i dont know how to do that :(
Mehek14
  • Mehek14
\(\dfrac{4}{3}*\dfrac{3}{4z+1}\)
anonymous
  • anonymous
what is z
anonymous
  • anonymous
im sorry i am a very slow learner and horrible at math
anonymous
  • anonymous
can you explain more?
Mehek14
  • Mehek14
hold on
anonymous
  • anonymous
k
anonymous
  • anonymous
Which statement is true about the equation fraction 3 over 4z − fraction 1 over 4z + 1 = fraction 2 over 4z + 1? It has no solution. It has one solution. It has two solutions. It has infinitely many solutions.
anonymous
  • anonymous
lol i just wanna see it cuz the other one went up
Mehek14
  • Mehek14
I'm getting no solution
anonymous
  • anonymous
@Mehek14 thanks for trying
Mehek14
  • Mehek14
np
anonymous
  • anonymous
@Nnesha can you help
anonymous
  • anonymous
@brittanyirvinn @beckyjeanwilson @brybry245 @brandonptv3
anonymous
  • anonymous
it this question below Which statement is true about the equation fraction 3 over 4z − fraction 1 over 4z + 1 = fraction 2 over 4z + 1? It has no solution. It has one solution. It has two solutions. It has infinitely many solutions.
Nnesha
  • Nnesha
\[\huge\rm \frac{ 3 }{ 4z } -\frac{ 1 }{4z+1 } = \frac{ 2 }{ 4z+1 }\] like this ?
anonymous
  • anonymous
yeah but i dont get how to do that
Nnesha
  • Nnesha
first of all solve left side find common denominator
anonymous
  • anonymous
4z + 4z
Nnesha
  • Nnesha
when you multiply same bases you should add their exponents so 4z times 4z= ?
anonymous
  • anonymous
16z
Nnesha
  • Nnesha
common denominator is 4z(4z+1) so distribute parentheses by 4z when u multiply same bases you should add exponents \[\huge\rm x^m \times x^n = x^{m+n}\]
anonymous
  • anonymous
wow i mind is BLOWN!!!
anonymous
  • anonymous
i dont get it :(
anonymous
  • anonymous
im sry
Nnesha
  • Nnesha
4z times 4z =(4 times 4)(z times z)
Nnesha
  • Nnesha
z times z equal what ?
anonymous
  • anonymous
16 and 2z
anonymous
  • anonymous
z=8?
Nnesha
  • Nnesha
nope add their exponents z is same as z to the one power \[z^1 \times z^1 = z^{1+1}\]
anonymous
  • anonymous
ok i dont get it im sorry
anonymous
  • anonymous
if you dont want to help me thats okay cuz this will take a long time
Nnesha
  • Nnesha
here are examples \[\huge\rm x^2 \times x^2 = x^{2+2}\] \[\huge\rm 2^3 \times 2^3 = 2^{3+3}\] this is an exponent rule when we multiply same bases we add their exponents
anonymous
  • anonymous
ok
Nnesha
  • Nnesha
|dw:1437580573519:dw|
Nnesha
  • Nnesha
so z times z=what ?
anonymous
  • anonymous
z to the power of 2 ?!?
Nnesha
  • Nnesha
yes right
Nnesha
  • Nnesha
so 16z^2 + 4z
anonymous
  • anonymous
YAYY FINALLY I GOT SOMETHING RIGHT!
anonymous
  • anonymous
300z
Nnesha
  • Nnesha
\[\huge\rm \frac{ 3 }{ 4z } -\frac{ 1 }{4z+1 } \] \[\frac{ ? }{ 16z^2 +4z }\] 16z^2 +4z is a denominator now at the numerator multiply first numerator of first fraction by the denominator of 2nd fraction and *multiply numerator of 2nd fraction by the denominator of first fraction
Nnesha
  • Nnesha
what about 300z?
anonymous
  • anonymous
16z*16z=256z+4z=300Z
Nnesha
  • Nnesha
what how did you get two 16z's ?
anonymous
  • anonymous
cuz 16z to the power of two
Nnesha
  • Nnesha
now only z is to the 2 power not 16
Nnesha
  • Nnesha
16z^2 +4z is right leave it as it is
anonymous
  • anonymous
ok
Nnesha
  • Nnesha
|dw:1437581002932:dw| now multiply numerator of first fraction by the denominator of 2nd fraction and multiply numerator of 2nd fraction by the denominator of 1st fraction it's like cross multiplication but don't forget to carry down the negative sign
anonymous
  • anonymous
1 Cancel 1 on both sides 34z−14z=24z 2 Simplify 34z to 3z4 3z4−14z=24z 3 Simplify 14z to z4 3z4−z4=24z 4 Simplify 24 to 12 3z4−z4=12z 5 Simplify 12z to z2 3z4−z4=z2 6 Simplify 3z4−z4 to z2 z2=z2 7 Since both sides equal, there are infinitely many solutions Infinitely Many Solutions
anonymous
  • anonymous
is that right?
Nnesha
  • Nnesha
i don't understand first sentence which 2 1's cancels out ?
anonymous
  • anonymous
the one from 4z +1
Nnesha
  • Nnesha
nope you are not allowed to cancel out 1 of 4z+1
anonymous
  • anonymous
ok
anonymous
  • anonymous
instead can you help with this one
anonymous
  • anonymous
The work of a student to solve the equation 2(3x − 4) = 8 + 2x + 4 is shown below: Step 1: 2(3x − 4) = 8 + 2x + 4 Step 2: 5x − 6 = 12 + 2x Step 3: 5x − 2x = 12 + 6 Step 4: 3x = 18 Step 5: x = 6 In which step did the student first make an error and what is the correct step? Step 2; 6x − 6 = 2(6 + x + 2) Step 2; 6x − 8 = 12 + 2x Step 3; 5x − 2x = 12 − 6 Step 3; 5x + 2x = 12 + 6
anonymous
  • anonymous
i think step 2
anonymous
  • anonymous
what do you think
Nnesha
  • Nnesha
if you don't know how to solve previous one you will not understand da next one
Nnesha
  • Nnesha
why do you think its step 2 ?
anonymous
  • anonymous
cuz there sould not be a five cuz of distributive propoerty
Nnesha
  • Nnesha
yep right
anonymous
  • anonymous
thanks how about this
anonymous
  • anonymous
solve it tell me what you think ill tell you what i think: Two lines, C and D, are represented by the equations given below: Line C: y = x + 14 Line D: y = 3x + 2 Which of the following shows the solution to the system of equations and explains why? (6, 20), because both lines pass through this point (6, 20), because the point does not lie on any axis (3, 11), because one of the lines passes through this point (3, 11), because the point lies between the two axes
anonymous
  • anonymous
i think it is b and you???
anonymous
  • anonymous
@ash2326 @AliceCullen @acxbox22 @AaronAndyson @Albany_Goon @automaticloveletter
anonymous
  • anonymous
Two lines, C and D, are represented by the equations given below: Line C: y = x + 14 Line D: y = 3x + 2 Which of the following shows the solution to the system of equations and explains why? (6, 20), because both lines pass through this point (6, 20), because the point does not lie on any axis (3, 11), because one of the lines passes through this point (3, 11), because the point lies between the two axes solve it tell me which one you think
Nnesha
  • Nnesha
why do you think its b?
anonymous
  • anonymous
@SolomonZelman @Smita12 @sweetburger
anonymous
  • anonymous
@paki
anonymous
  • anonymous
@poopsiedoodle @TwiztTiez
anonymous
  • anonymous
@teddydaddy23 @Teddyiswatshecallsme
anonymous
  • anonymous
@jillina29
anonymous
  • anonymous
help!
Nnesha
  • Nnesha
better to post your work instead tagging other people
Nnesha
  • Nnesha
i asked you a question
anonymous
  • anonymous
Two lines, C and D, are represented by the equations given below: Line C: y = x + 14 Line D: y = 3x + 2 Which of the following shows the solution to the system of equations and explains why? (6, 20), because both lines pass through this point (6, 20), because the point does not lie on any axis (3, 11), because one of the lines passes through this point (3, 11), because the point lies between the two axes tell me what you think
Nnesha
  • Nnesha
Why do you think its b ? what is solution ? how do you find solution on the graph ?
anonymous
  • anonymous
i dont know thats why i want you to see if it correct i did it in my head
Nnesha
  • Nnesha
so stop guessing
Nnesha
  • Nnesha
solution is a point where both lines intersect
anonymous
  • anonymous
if your not going to help me you can leave i want to know how to solve it
Nnesha
  • Nnesha
so what's the point of asking question
Nnesha
  • Nnesha
i never said *i'm not gonna help you*
anonymous
  • anonymous
to get someone to help me not yell at me or be rude
Nnesha
  • Nnesha
i'm not yelling at you
Nnesha
  • Nnesha
and you know what is rude tagging other people when someone already trying to help you
anonymous
  • anonymous
@automaticloveletter can you help
anonymous
  • anonymous
Two lines, C and D, are represented by the equations given below: Line C: y = x + 14 Line D: y = 3x + 2 Which of the following shows the solution to the system of equations and explains why? (6, 20), because both lines pass through this point (6, 20), because the point does not lie on any axis (3, 11), because one of the lines passes through this point (3, 11), because the point lies between the two axes
automaticloveletter
  • automaticloveletter
Both equations equal y so this means we can combine them together. Line C: y = x + 14 Line D: y = 3x + 2 Will become: x+14 = 3x+2 Then you'd subtract both sides by 3x: (x+14−3x=3x+2−3x−2x+14=2) Next subtract by 14 on both sides: (−2x+14−14=2−14−2x=−12) After that you'd divide both sides by -2: −2x/−2=−12/−2 x = 6 So now we have x all you have to do now is calculate for y and to do that put the value of x (6) in the equations: y = 6 + 14 (20) y = 3*6 + 2 (20) y = 20 The solution is (6,20) Your answer would be A.
anonymous
  • anonymous
Wow your give please give me time to read this
automaticloveletter
  • automaticloveletter
It's pretty simple but I hope I helped.
anonymous
  • anonymous
very much
anonymous
  • anonymous
will you keep helping
automaticloveletter
  • automaticloveletter
Depends. I just finished this material yesterday so yeah.
anonymous
  • anonymous
oh you did you in 7 grade
automaticloveletter
  • automaticloveletter
8th
automaticloveletter
  • automaticloveletter
Well 9th but whatever, just tag me in your questions and I'll try to help.
anonymous
  • anonymous
Peter is 2 years older than Winnie. Peter's age is 16 years less than seven times Winnie's age. The equations below model the relationship between Peter's age (p) and Winnie's age (w): p = w + 2 p = 7w − 16 Which is a possible correct method to find Peter's and Winnie's ages? Solve w + 2 = 7w − 16 to find the value of w. Solve p + 2 = 7p − 16 to find the value of p. Write the points where the graphs of the equations intersect the x axis. Write the points where the graphs of the equations intersect the y axis.
anonymous
  • anonymous
@automaticloveletter
anonymous
  • anonymous
lolz
anonymous
  • anonymous
@automaticloveletter
anonymous
  • anonymous
you stil;l there?
automaticloveletter
  • automaticloveletter
I think it's A
anonymous
  • anonymous
ok
anonymous
  • anonymous
but why
anonymous
  • anonymous
A pair of equations is shown below: y = 7x − 8 y = 5x − 2 Part A: Explain how you will solve the pair of equations by substitution or elimination. Show all the steps and write the solution. Part B: If the two equations are graphed, at what point will the lines representing the two equations intersect? Explain your answer
automaticloveletter
  • automaticloveletter
Peter is 2 years older than Winnie. p = w + 2 Peter's age is 16 years less than seven times Winnie's age. 7w − 16 C and D don't make sense to me so your best choices would be A or B but I'd go with A.
anonymous
  • anonymous
thats the next one
automaticloveletter
  • automaticloveletter
Alright so basically what it's asking you is: Solve. Show Your Work. Answer. Since both equations equal y we can combine them (like I did before, remember?)
anonymous
  • anonymous
yeah i do cause you explained it clear #thebest
anonymous
  • anonymous
wait can you show me how to do either subtitution or elimination
automaticloveletter
  • automaticloveletter
Alright, so now combine them for me.
anonymous
  • anonymous
y=12x-10
automaticloveletter
  • automaticloveletter
No don't add them just put them together
anonymous
  • anonymous
oh
anonymous
  • anonymous
7x-8=5x-2
anonymous
  • anonymous
correct?
automaticloveletter
  • automaticloveletter
It's easy all you do is look at both of them y = 7x − 8 y = 5x − 2 Take both y's out = 7x − 8 = 5x − 2 And take the first = sign out 7x − 8 = 5x − 2
automaticloveletter
  • automaticloveletter
Good job.
anonymous
  • anonymous
ok was that elimination or substitutuion or None.
automaticloveletter
  • automaticloveletter
Now we have to subtract 5x from both sides. 7x−8−5x 5x−2−5x = 2x−8=−2
anonymous
  • anonymous
2x-8=-2
anonymous
  • anonymous
oh wait you said that lol
automaticloveletter
  • automaticloveletter
I think it's substitution
anonymous
  • anonymous
k
anonymous
  • anonymous
so can you wrap it all up so i can read it together
automaticloveletter
  • automaticloveletter
Next step is to add 8 to both sides 2x−8+8 −2+8 2x=6 After that just divide both by 2 2x/2 6/2 x = 3 Now we got 3 for x so all we have to do is put 3 into the equations to solve for y.
automaticloveletter
  • automaticloveletter
Can you do that? Or do you want me to show you that step as well?
anonymous
  • anonymous
ok
anonymous
  • anonymous
ok you know what my sis will help me wit this it too hard and we like not in person so her do this one:\\ Two equations are given below: a − 3b = 4 a = b − 2 What is the solution to the set of equations in the form (a, b)? (−2, −2) (−3, −1) (−9, −7) (−5, −3)
automaticloveletter
  • automaticloveletter
I'll just do it for you y = 7*3 − 8 (13) y = 5*3 − 2 (13) y = 13 Solution is (3,13) so this is where they would intersect on a graph.
anonymous
  • anonymous
ok thanks
automaticloveletter
  • automaticloveletter
You're welcome. I have to do my own homework now so good luck.
anonymous
  • anonymous
wait how did you get 3
anonymous
  • anonymous
@automaticloveletter how did you get three
anonymous
  • anonymous
nm

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