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anonymous

  • one year ago

fan medal and testimony help!!!. What is the solution to the equation 1.2m − 0.8 = −2.0m? m = 0.25 m = 0.4 m = 1 m = 4

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  1. Mehek14
    • one year ago
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    first add 1.2 + 2

  2. anonymous
    • one year ago
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    3.2

  3. Mehek14
    • one year ago
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    and add 0 + 0.8

  4. anonymous
    • one year ago
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    0.8

  5. Mehek14
    • one year ago
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    so you have \(3.2m = 0.8\) now divide \(\dfrac{0.8}{3.2}\)

  6. anonymous
    • one year ago
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    0.25

  7. Mehek14
    • one year ago
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    \(m=0.25\)

  8. anonymous
    • one year ago
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    thanks can you help with a couple more

  9. Mehek14
    • one year ago
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    sure

  10. anonymous
    • one year ago
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    thanks your great!

  11. Mehek14
    • one year ago
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    ^_^

  12. anonymous
    • one year ago
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    Which statement is true about the equation fraction 3 over 4z − fraction 1 over 4z + 1 = fraction 2 over 4z + 1? It has no solution. It has one solution. It has two solutions. It has infinitely many solutions.

  13. anonymous
    • one year ago
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    DO YOU KNOW HOW TO

  14. anonymous
    • one year ago
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    oops cap lock sorry

  15. Mehek14
    • one year ago
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    \(\dfrac{3}{4z}-\dfrac{1}{4z+1}=\dfrac{2}{4z+1}\)

  16. Mehek14
    • one year ago
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    \(\dfrac{3}{4z}=\dfrac{3}{4z+1}\)

  17. anonymous
    • one year ago
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    i dont know how to do that :(

  18. Mehek14
    • one year ago
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    \(\dfrac{4}{3}*\dfrac{3}{4z+1}\)

  19. anonymous
    • one year ago
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    what is z

  20. anonymous
    • one year ago
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    im sorry i am a very slow learner and horrible at math

  21. anonymous
    • one year ago
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    can you explain more?

  22. Mehek14
    • one year ago
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    hold on

  23. anonymous
    • one year ago
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    k

  24. anonymous
    • one year ago
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    Which statement is true about the equation fraction 3 over 4z − fraction 1 over 4z + 1 = fraction 2 over 4z + 1? It has no solution. It has one solution. It has two solutions. It has infinitely many solutions.

  25. anonymous
    • one year ago
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    lol i just wanna see it cuz the other one went up

  26. Mehek14
    • one year ago
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    I'm getting no solution

  27. anonymous
    • one year ago
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    @Mehek14 thanks for trying

  28. Mehek14
    • one year ago
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    np

  29. anonymous
    • one year ago
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    @Nnesha can you help

  30. anonymous
    • one year ago
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    @brittanyirvinn @beckyjeanwilson @brybry245 @brandonptv3

  31. anonymous
    • one year ago
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    it this question below Which statement is true about the equation fraction 3 over 4z − fraction 1 over 4z + 1 = fraction 2 over 4z + 1? It has no solution. It has one solution. It has two solutions. It has infinitely many solutions.

  32. Nnesha
    • one year ago
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    \[\huge\rm \frac{ 3 }{ 4z } -\frac{ 1 }{4z+1 } = \frac{ 2 }{ 4z+1 }\] like this ?

  33. anonymous
    • one year ago
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    yeah but i dont get how to do that

  34. Nnesha
    • one year ago
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    first of all solve left side find common denominator

  35. anonymous
    • one year ago
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    4z + 4z

  36. Nnesha
    • one year ago
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    when you multiply same bases you should add their exponents so 4z times 4z= ?

  37. anonymous
    • one year ago
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    16z

  38. Nnesha
    • one year ago
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    common denominator is 4z(4z+1) so distribute parentheses by 4z when u multiply same bases you should add exponents \[\huge\rm x^m \times x^n = x^{m+n}\]

  39. anonymous
    • one year ago
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    wow i mind is BLOWN!!!

  40. anonymous
    • one year ago
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    i dont get it :(

  41. anonymous
    • one year ago
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    im sry

  42. Nnesha
    • one year ago
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    4z times 4z =(4 times 4)(z times z)

  43. Nnesha
    • one year ago
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    z times z equal what ?

  44. anonymous
    • one year ago
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    16 and 2z

  45. anonymous
    • one year ago
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    z=8?

  46. Nnesha
    • one year ago
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    nope add their exponents z is same as z to the one power \[z^1 \times z^1 = z^{1+1}\]

  47. anonymous
    • one year ago
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    ok i dont get it im sorry

  48. anonymous
    • one year ago
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    if you dont want to help me thats okay cuz this will take a long time

  49. Nnesha
    • one year ago
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    here are examples \[\huge\rm x^2 \times x^2 = x^{2+2}\] \[\huge\rm 2^3 \times 2^3 = 2^{3+3}\] this is an exponent rule when we multiply same bases we add their exponents

  50. anonymous
    • one year ago
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    ok

  51. Nnesha
    • one year ago
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    |dw:1437580573519:dw|

  52. Nnesha
    • one year ago
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    so z times z=what ?

  53. anonymous
    • one year ago
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    z to the power of 2 ?!?

  54. Nnesha
    • one year ago
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    yes right

  55. Nnesha
    • one year ago
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    so 16z^2 + 4z

  56. anonymous
    • one year ago
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    YAYY FINALLY I GOT SOMETHING RIGHT!

  57. anonymous
    • one year ago
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    300z

  58. Nnesha
    • one year ago
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    \[\huge\rm \frac{ 3 }{ 4z } -\frac{ 1 }{4z+1 } \] \[\frac{ ? }{ 16z^2 +4z }\] 16z^2 +4z is a denominator now at the numerator multiply first numerator of first fraction by the denominator of 2nd fraction and *multiply numerator of 2nd fraction by the denominator of first fraction

  59. Nnesha
    • one year ago
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    what about 300z?

  60. anonymous
    • one year ago
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    16z*16z=256z+4z=300Z

  61. Nnesha
    • one year ago
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    what how did you get two 16z's ?

  62. anonymous
    • one year ago
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    cuz 16z to the power of two

  63. Nnesha
    • one year ago
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    now only z is to the 2 power not 16

  64. Nnesha
    • one year ago
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    16z^2 +4z is right leave it as it is

  65. anonymous
    • one year ago
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    ok

  66. Nnesha
    • one year ago
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    |dw:1437581002932:dw| now multiply numerator of first fraction by the denominator of 2nd fraction and multiply numerator of 2nd fraction by the denominator of 1st fraction it's like cross multiplication but don't forget to carry down the negative sign

  67. anonymous
    • one year ago
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    1 Cancel 1 on both sides 34z−14z=24z 2 Simplify 34z to 3z4 3z4−14z=24z 3 Simplify 14z to z4 3z4−z4=24z 4 Simplify 24 to 12 3z4−z4=12z 5 Simplify 12z to z2 3z4−z4=z2 6 Simplify 3z4−z4 to z2 z2=z2 7 Since both sides equal, there are infinitely many solutions Infinitely Many Solutions

  68. anonymous
    • one year ago
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    is that right?

  69. Nnesha
    • one year ago
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    i don't understand first sentence which 2 1's cancels out ?

  70. anonymous
    • one year ago
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    the one from 4z +1

  71. Nnesha
    • one year ago
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    nope you are not allowed to cancel out 1 of 4z+1

  72. anonymous
    • one year ago
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    ok

  73. anonymous
    • one year ago
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    instead can you help with this one

  74. anonymous
    • one year ago
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    The work of a student to solve the equation 2(3x − 4) = 8 + 2x + 4 is shown below: Step 1: 2(3x − 4) = 8 + 2x + 4 Step 2: 5x − 6 = 12 + 2x Step 3: 5x − 2x = 12 + 6 Step 4: 3x = 18 Step 5: x = 6 In which step did the student first make an error and what is the correct step? Step 2; 6x − 6 = 2(6 + x + 2) Step 2; 6x − 8 = 12 + 2x Step 3; 5x − 2x = 12 − 6 Step 3; 5x + 2x = 12 + 6

  75. anonymous
    • one year ago
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    i think step 2

  76. anonymous
    • one year ago
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    what do you think

  77. Nnesha
    • one year ago
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    if you don't know how to solve previous one you will not understand da next one

  78. Nnesha
    • one year ago
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    why do you think its step 2 ?

  79. anonymous
    • one year ago
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    cuz there sould not be a five cuz of distributive propoerty

  80. Nnesha
    • one year ago
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    yep right

  81. anonymous
    • one year ago
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    thanks how about this

  82. anonymous
    • one year ago
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    solve it tell me what you think ill tell you what i think: Two lines, C and D, are represented by the equations given below: Line C: y = x + 14 Line D: y = 3x + 2 Which of the following shows the solution to the system of equations and explains why? (6, 20), because both lines pass through this point (6, 20), because the point does not lie on any axis (3, 11), because one of the lines passes through this point (3, 11), because the point lies between the two axes

  83. anonymous
    • one year ago
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    i think it is b and you???

  84. anonymous
    • one year ago
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    @ash2326 @AliceCullen @acxbox22 @AaronAndyson @Albany_Goon @automaticloveletter

  85. anonymous
    • one year ago
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    Two lines, C and D, are represented by the equations given below: Line C: y = x + 14 Line D: y = 3x + 2 Which of the following shows the solution to the system of equations and explains why? (6, 20), because both lines pass through this point (6, 20), because the point does not lie on any axis (3, 11), because one of the lines passes through this point (3, 11), because the point lies between the two axes solve it tell me which one you think

  86. Nnesha
    • one year ago
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    why do you think its b?

  87. anonymous
    • one year ago
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    @SolomonZelman @Smita12 @sweetburger

  88. anonymous
    • one year ago
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    @paki

  89. anonymous
    • one year ago
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    @poopsiedoodle @TwiztTiez

  90. anonymous
    • one year ago
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    @teddydaddy23 @Teddyiswatshecallsme

  91. anonymous
    • one year ago
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    @jillina29

  92. anonymous
    • one year ago
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    help!

  93. Nnesha
    • one year ago
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    better to post your work instead tagging other people

  94. Nnesha
    • one year ago
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    i asked you a question

  95. anonymous
    • one year ago
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    Two lines, C and D, are represented by the equations given below: Line C: y = x + 14 Line D: y = 3x + 2 Which of the following shows the solution to the system of equations and explains why? (6, 20), because both lines pass through this point (6, 20), because the point does not lie on any axis (3, 11), because one of the lines passes through this point (3, 11), because the point lies between the two axes tell me what you think

  96. Nnesha
    • one year ago
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    Why do you think its b ? what is solution ? how do you find solution on the graph ?

  97. anonymous
    • one year ago
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    i dont know thats why i want you to see if it correct i did it in my head

  98. Nnesha
    • one year ago
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    so stop guessing

  99. Nnesha
    • one year ago
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    solution is a point where both lines intersect

  100. anonymous
    • one year ago
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    if your not going to help me you can leave i want to know how to solve it

  101. Nnesha
    • one year ago
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    so what's the point of asking question

  102. Nnesha
    • one year ago
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    i never said *i'm not gonna help you*

  103. anonymous
    • one year ago
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    to get someone to help me not yell at me or be rude

  104. Nnesha
    • one year ago
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    i'm not yelling at you

  105. Nnesha
    • one year ago
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    and you know what is rude tagging other people when someone already trying to help you

  106. anonymous
    • one year ago
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    @automaticloveletter can you help

  107. anonymous
    • one year ago
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    Two lines, C and D, are represented by the equations given below: Line C: y = x + 14 Line D: y = 3x + 2 Which of the following shows the solution to the system of equations and explains why? (6, 20), because both lines pass through this point (6, 20), because the point does not lie on any axis (3, 11), because one of the lines passes through this point (3, 11), because the point lies between the two axes

  108. automaticloveletter
    • one year ago
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    Both equations equal y so this means we can combine them together. Line C: y = x + 14 Line D: y = 3x + 2 Will become: x+14 = 3x+2 Then you'd subtract both sides by 3x: (x+14−3x=3x+2−3x−2x+14=2) Next subtract by 14 on both sides: (−2x+14−14=2−14−2x=−12) After that you'd divide both sides by -2: −2x/−2=−12/−2 x = 6 So now we have x all you have to do now is calculate for y and to do that put the value of x (6) in the equations: y = 6 + 14 (20) y = 3*6 + 2 (20) y = 20 The solution is (6,20) Your answer would be A.

  109. anonymous
    • one year ago
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    Wow your give please give me time to read this

  110. automaticloveletter
    • one year ago
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    It's pretty simple but I hope I helped.

  111. anonymous
    • one year ago
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    very much

  112. anonymous
    • one year ago
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    will you keep helping

  113. automaticloveletter
    • one year ago
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    Depends. I just finished this material yesterday so yeah.

  114. anonymous
    • one year ago
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    oh you did you in 7 grade

  115. automaticloveletter
    • one year ago
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    8th

  116. automaticloveletter
    • one year ago
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    Well 9th but whatever, just tag me in your questions and I'll try to help.

  117. anonymous
    • one year ago
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    Peter is 2 years older than Winnie. Peter's age is 16 years less than seven times Winnie's age. The equations below model the relationship between Peter's age (p) and Winnie's age (w): p = w + 2 p = 7w − 16 Which is a possible correct method to find Peter's and Winnie's ages? Solve w + 2 = 7w − 16 to find the value of w. Solve p + 2 = 7p − 16 to find the value of p. Write the points where the graphs of the equations intersect the x axis. Write the points where the graphs of the equations intersect the y axis.

  118. anonymous
    • one year ago
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    @automaticloveletter

  119. anonymous
    • one year ago
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    lolz

  120. anonymous
    • one year ago
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    @automaticloveletter

  121. anonymous
    • one year ago
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    you stil;l there?

  122. automaticloveletter
    • one year ago
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    I think it's A

  123. anonymous
    • one year ago
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    ok

  124. anonymous
    • one year ago
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    but why

  125. anonymous
    • one year ago
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    A pair of equations is shown below: y = 7x − 8 y = 5x − 2 Part A: Explain how you will solve the pair of equations by substitution or elimination. Show all the steps and write the solution. Part B: If the two equations are graphed, at what point will the lines representing the two equations intersect? Explain your answer

  126. automaticloveletter
    • one year ago
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    Peter is 2 years older than Winnie. p = w + 2 Peter's age is 16 years less than seven times Winnie's age. 7w − 16 C and D don't make sense to me so your best choices would be A or B but I'd go with A.

  127. anonymous
    • one year ago
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    thats the next one

  128. automaticloveletter
    • one year ago
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    Alright so basically what it's asking you is: Solve. Show Your Work. Answer. Since both equations equal y we can combine them (like I did before, remember?)

  129. anonymous
    • one year ago
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    yeah i do cause you explained it clear #thebest

  130. anonymous
    • one year ago
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    wait can you show me how to do either subtitution or elimination

  131. automaticloveletter
    • one year ago
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    Alright, so now combine them for me.

  132. anonymous
    • one year ago
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    y=12x-10

  133. automaticloveletter
    • one year ago
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    No don't add them just put them together

  134. anonymous
    • one year ago
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    oh

  135. anonymous
    • one year ago
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    7x-8=5x-2

  136. anonymous
    • one year ago
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    correct?

  137. automaticloveletter
    • one year ago
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    It's easy all you do is look at both of them y = 7x − 8 y = 5x − 2 Take both y's out = 7x − 8 = 5x − 2 And take the first = sign out 7x − 8 = 5x − 2

  138. automaticloveletter
    • one year ago
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    Good job.

  139. anonymous
    • one year ago
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    ok was that elimination or substitutuion or None.

  140. automaticloveletter
    • one year ago
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    Now we have to subtract 5x from both sides. 7x−8−5x 5x−2−5x = 2x−8=−2

  141. anonymous
    • one year ago
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    2x-8=-2

  142. anonymous
    • one year ago
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    oh wait you said that lol

  143. automaticloveletter
    • one year ago
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    I think it's substitution

  144. anonymous
    • one year ago
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    k

  145. anonymous
    • one year ago
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    so can you wrap it all up so i can read it together

  146. automaticloveletter
    • one year ago
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    Next step is to add 8 to both sides 2x−8+8 −2+8 2x=6 After that just divide both by 2 2x/2 6/2 x = 3 Now we got 3 for x so all we have to do is put 3 into the equations to solve for y.

  147. automaticloveletter
    • one year ago
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    Can you do that? Or do you want me to show you that step as well?

  148. anonymous
    • one year ago
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    ok

  149. anonymous
    • one year ago
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    ok you know what my sis will help me wit this it too hard and we like not in person so her do this one:\\ Two equations are given below: a − 3b = 4 a = b − 2 What is the solution to the set of equations in the form (a, b)? (−2, −2) (−3, −1) (−9, −7) (−5, −3)

  150. automaticloveletter
    • one year ago
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    I'll just do it for you y = 7*3 − 8 (13) y = 5*3 − 2 (13) y = 13 Solution is (3,13) so this is where they would intersect on a graph.

  151. anonymous
    • one year ago
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    ok thanks

  152. automaticloveletter
    • one year ago
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    You're welcome. I have to do my own homework now so good luck.

  153. anonymous
    • one year ago
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    wait how did you get 3

  154. anonymous
    • one year ago
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    @automaticloveletter how did you get three

  155. anonymous
    • one year ago
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    nm

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