## anonymous one year ago A bowl contains candies of the same size in three flavors: orange, strawberry, and pineapple. If the probability of randomly pulling out an orange candy is 1 over 9, and the probability of randomly pulling out a strawberry candy is 3 over 9, what is the probability of randomly pulling out a pineapple candy?

1. anonymous

so would it be 4/9 ? cause i did 1 + 3 and kept the denominator the same.

2. anonymous

The sum of all the probabilities must be 1. What do think the answer is?

3. anonymous

why would it be 5/9 ? @pinkbubbles

4. anonymous

P(orange) + P(strawberry) + P(pineapple) = 1 1/9 + 3/9 + P(pineapple) = 1 Understand?

5. anonymous

i think so. so would my answer then be 2/9?

6. anonymous

Not quite.$\frac{ 1 }{ 9 } + \frac{ 3 }{ 9 } + P(pineapple) = \frac{ 9 }{ 9 }$What is P(pineapple)?

7. anonymous

oh I think I got it now, so pineapple is 5/9 right?

8. anonymous

Bingo!! Well done.

9. anonymous

thank you, I really understand it now! :)

10. anonymous

That's the most important thing. Keep up the good work.