anonymous
  • anonymous
A bowl contains candies of the same size in three flavors: orange, strawberry, and pineapple. If the probability of randomly pulling out an orange candy is 1 over 9, and the probability of randomly pulling out a strawberry candy is 3 over 9, what is the probability of randomly pulling out a pineapple candy?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
so would it be 4/9 ? cause i did 1 + 3 and kept the denominator the same.
anonymous
  • anonymous
The sum of all the probabilities must be 1. What do think the answer is?
anonymous
  • anonymous
why would it be 5/9 ? @pinkbubbles

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More answers

anonymous
  • anonymous
P(orange) + P(strawberry) + P(pineapple) = 1 1/9 + 3/9 + P(pineapple) = 1 Understand?
anonymous
  • anonymous
i think so. so would my answer then be 2/9?
anonymous
  • anonymous
Not quite.\[\frac{ 1 }{ 9 } + \frac{ 3 }{ 9 } + P(pineapple) = \frac{ 9 }{ 9 }\]What is P(pineapple)?
anonymous
  • anonymous
oh I think I got it now, so pineapple is 5/9 right?
anonymous
  • anonymous
Bingo!! Well done.
anonymous
  • anonymous
thank you, I really understand it now! :)
anonymous
  • anonymous
That's the most important thing. Keep up the good work.

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