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anonymous
 one year ago
A bowl contains candies of the same size in three flavors: orange, strawberry, and pineapple. If the probability of randomly pulling out an orange candy is 1 over 9, and the probability of randomly pulling out a strawberry candy is 3 over 9, what is the probability of randomly pulling out a pineapple candy?
anonymous
 one year ago
A bowl contains candies of the same size in three flavors: orange, strawberry, and pineapple. If the probability of randomly pulling out an orange candy is 1 over 9, and the probability of randomly pulling out a strawberry candy is 3 over 9, what is the probability of randomly pulling out a pineapple candy?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so would it be 4/9 ? cause i did 1 + 3 and kept the denominator the same.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The sum of all the probabilities must be 1. What do think the answer is?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0why would it be 5/9 ? @pinkbubbles

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0P(orange) + P(strawberry) + P(pineapple) = 1 1/9 + 3/9 + P(pineapple) = 1 Understand?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i think so. so would my answer then be 2/9?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Not quite.\[\frac{ 1 }{ 9 } + \frac{ 3 }{ 9 } + P(pineapple) = \frac{ 9 }{ 9 }\]What is P(pineapple)?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh I think I got it now, so pineapple is 5/9 right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thank you, I really understand it now! :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That's the most important thing. Keep up the good work.
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