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anonymous

  • one year ago

The function H(t) = −16t2 + 96t + 80 shows the height H(t), in feet, of a projectile after t seconds. A second object moves in the air along a path represented by g(t) = 31 + 32.2t, where g(t) is the height, in feet, of the object from the ground at time t seconds. Part A: Create a table using integers 2 through 5 for the 2 functions. Between what 2 seconds is the solution to H(t) = g(t) located? How do you know? (6 points) Part B: Explain what the solution from Part A means in the context of the problem. (4 points) Can you pplease help mE??? @triciaal

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  1. anonymous
    • one year ago
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    HELP ME?

  2. anonymous
    • one year ago
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    @Abhisar

  3. anonymous
    • one year ago
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    hello

  4. anonymous
    • one year ago
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    hi

  5. anonymous
    • one year ago
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    can you help?

  6. anonymous
    • one year ago
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    im sorry im not good at these types

  7. anonymous
    • one year ago
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    its okay

  8. anonymous
    • one year ago
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    how about you ?

  9. anonymous
    • one year ago
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    @pooja195 can you help?

  10. anonymous
    • one year ago
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    dude can anyone help? im really stuck on this

  11. anonymous
    • one year ago
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    @abb0t can you please help me?

  12. anonymous
    • one year ago
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    @mathstudent55

  13. anonymous
    • one year ago
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    please help? @mathstudent55 @abb0t

  14. anonymous
    • one year ago
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    Hi

  15. anonymous
    • one year ago
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    @triciaal can you help?

  16. triciaal
    • one year ago
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    going through the closed questions just did this think yesterday

  17. triciaal
    • one year ago
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    new part A do the table

  18. triciaal
    • one year ago
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    |dw:1437583979413:dw|

  19. triciaal
    • one year ago
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    fill out the table completely look at the values of H(t) and g(t) and see where they are approximately equal then look at the "t" column to see between what 2 integers

  20. anonymous
    • one year ago
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    I have no clue

  21. triciaal
    • one year ago
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    what do you mean by that? did you actually read my response?

  22. triciaal
    • one year ago
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    |dw:1437586186176:dw|

  23. anonymous
    • one year ago
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    i dont know how you did that, the graph and stuff. i dont know how that correlates to the question @triciaal

  24. anonymous
    • one year ago
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    @abb0t Could you help???

  25. anonymous
    • one year ago
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    i can help

  26. anonymous
    • one year ago
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    @lealealea222

  27. anonymous
    • one year ago
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    THANKYOU

  28. anonymous
    • one year ago
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    np

  29. anonymous
    • one year ago
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    she took the 2 expressions from the begging and substituted numbers 2 through 5 for t so u just solve and make the table

  30. anonymous
    • one year ago
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    begining

  31. anonymous
    • one year ago
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    okay i see that

  32. anonymous
    • one year ago
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    so now u just solve the equations and write the numbers in for the table

  33. anonymous
    • one year ago
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    for example for the first equation -16t^2+96t+80 ill substitute in 2

  34. anonymous
    • one year ago
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    -16(2)^2+96*2+80 -16*4+96*2+80 -64+192+80 208

  35. anonymous
    • one year ago
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    ok ill try, what number do i plug in for t?

  36. anonymous
    • one year ago
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    well i did 2 so u do 3 for t

  37. anonymous
    • one year ago
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    ill check it

  38. anonymous
    • one year ago
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    tell me when ur done

  39. anonymous
    • one year ago
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    -16(3)^2+96*3+80= 224

  40. anonymous
    • one year ago
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    yep so now do 4 for t then 5 for t after that

  41. anonymous
    • one year ago
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    ok

  42. anonymous
    • one year ago
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    what did u get

  43. anonymous
    • one year ago
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    -16(4)^2+96*4+80=208 -16(5)^2+96*5+80=160

  44. anonymous
    • one year ago
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    yep so now ur halfway done with part A

  45. anonymous
    • one year ago
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    yyay

  46. anonymous
    • one year ago
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    31+32.2*t is ur new equation so just do the same thing again t for 2 then 3 then 4 then 5

  47. anonymous
    • one year ago
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    -16(2)^2+96*2+80=208 -16(3)^2+96*3+80= 224 -16(4)^2+96*4+80=208 -16(5)^2+96*5+80=160

  48. anonymous
    • one year ago
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    no now use the equation 31+32.2t and plug in 2 then 3 then 4 then 5 for t

  49. anonymous
    • one year ago
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    ooh okay sorry

  50. anonymous
    • one year ago
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    sokay

  51. anonymous
    • one year ago
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    31+32.2(2)=95.4 31+32.2(3)=127.6 31+32.2(4)=159.8 31+32.2(5)=192

  52. anonymous
    • one year ago
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    good now plug those into the table

  53. anonymous
    • one year ago
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    how do i do that?

  54. anonymous
    • one year ago
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    it should look like this |dw:1437587989265:dw|

  55. anonymous
    • one year ago
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    Yea, is that what i put for part A?

  56. anonymous
    • one year ago
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    yep

  57. anonymous
    • one year ago
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    well u also have to say when are they equal

  58. anonymous
    • one year ago
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    ok awesome, im gonna write that down, then can we do part B?

  59. anonymous
    • one year ago
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    when do u think they are equal

  60. anonymous
    • one year ago
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    between which 2 t numbers

  61. anonymous
    • one year ago
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    erm they arent?

  62. anonymous
    • one year ago
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    not at that exact second (remeber t stands for seconds) but between which two numbers would it be. for example lets say u had 2 for one and 3 for the other at 1 sec then 3 for one of them and 2 for the other that means inbetween the seconds they were equal

  63. anonymous
    • one year ago
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    so between which seconds do u think they were equal

  64. anonymous
    • one year ago
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    H(t) 4 and G(t)5

  65. anonymous
    • one year ago
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    u just say between 4 and 5 seconds

  66. anonymous
    • one year ago
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    Awesome thanks

  67. anonymous
    • one year ago
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    Can you help with B?

  68. anonymous
    • one year ago
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    now lets do part b remmeber u have to explain how u got between 4 and 5 secs

  69. anonymous
    • one year ago
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    ok i got it down, now can you help with B?

  70. anonymous
    • one year ago
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    so what do u think it means that they where the same between 4 and 5 Hint:talk about what its about read the question to find what was happening

  71. anonymous
    • one year ago
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    It means the in feet, of projectile after 4 seconds, the same as A second object moves in the air along a path at 5 seconds

  72. anonymous
    • one year ago
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    yep good job!

  73. anonymous
    • one year ago
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    @lealealea222 before u close it can u do me a favor

  74. anonymous
    • one year ago
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    hello @lealealea222

  75. anonymous
    • one year ago
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    yea sure

  76. anonymous
    • one year ago
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    can u medal @triciaal instead of me

  77. anonymous
    • one year ago
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    um yea sure

  78. anonymous
    • one year ago
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    oh yea i see, she medaled you

  79. anonymous
    • one year ago
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    its just that i worked off of what he said so he helped first so he deserves it

  80. anonymous
    • one year ago
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    yea thats true, thankyou for helping

  81. anonymous
    • one year ago
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    np

  82. anonymous
    • one year ago
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    Don't forget to fan if you already haven't. Plus send me a message if you need more help @lealealea222

  83. anonymous
    • one year ago
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    ok :)

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