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Abhisar

  • one year ago

The position vector of a particle is given by \( r = r_0(1-at)t\) , where t is the time and a as well as \(r_0\) are constant. After what time the particle returns to the starting time

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  1. nincompoop
    • one year ago
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    latex is not displaying properly on my end

  2. nincompoop
    • one year ago
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    is that r naught (r sub zero)

  3. Abhisar
    • one year ago
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    Yes, it's r naught

  4. Abhisar
    • one year ago
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    I got it.

  5. nincompoop
    • one year ago
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    so t, a and r_0 are all constant? the english is badly phrased

  6. nincompoop
    • one year ago
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    \(test \)

  7. nincompoop
    • one year ago
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    okay now it is working

  8. Abhisar
    • one year ago
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    No only \(\sf r_0 ~and~ a\) are constants. \(\sf r = r_0t-r_0at^2\\ \Rightarrow (taking ~r=0) r_0t = r_0at^2 \\ \Rightarrow t =1/a\)

  9. nincompoop
    • one year ago
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    After what time the particle returns to the starting time

  10. Abhisar
    • one year ago
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    Yes, it shoud be t = 1/a

  11. Abhisar
    • one year ago
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    *should

  12. nincompoop
    • one year ago
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    i keep getting disconnected

  13. Abhisar
    • one year ago
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    It's ok, I solved it. Thanks for helping me though c:

  14. nincompoop
    • one year ago
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    by simplification, you are left with \(at=1 \)

  15. nincompoop
    • one year ago
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    your displacement must be set to zero (position function)

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