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Abhisar
 one year ago
The position vector of a particle is given by \( r = r_0(1at)t\) , where t is the time and a as well as \(r_0\) are constant. After what time the particle returns to the starting time
Abhisar
 one year ago
The position vector of a particle is given by \( r = r_0(1at)t\) , where t is the time and a as well as \(r_0\) are constant. After what time the particle returns to the starting time

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nincompoop
 one year ago
Best ResponseYou've already chosen the best response.2latex is not displaying properly on my end

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.2is that r naught (r sub zero)

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.2so t, a and r_0 are all constant? the english is badly phrased

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.2okay now it is working

Abhisar
 one year ago
Best ResponseYou've already chosen the best response.1No only \(\sf r_0 ~and~ a\) are constants. \(\sf r = r_0tr_0at^2\\ \Rightarrow (taking ~r=0) r_0t = r_0at^2 \\ \Rightarrow t =1/a\)

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.2After what time the particle returns to the starting time

Abhisar
 one year ago
Best ResponseYou've already chosen the best response.1Yes, it shoud be t = 1/a

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.2i keep getting disconnected

Abhisar
 one year ago
Best ResponseYou've already chosen the best response.1It's ok, I solved it. Thanks for helping me though c:

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.2by simplification, you are left with \(at=1 \)

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.2your displacement must be set to zero (position function)
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