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elleblythe

  • one year ago

How do we solve for this: lim(t->0) (tan2t)/3t

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  1. welshfella
    • one year ago
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    if we do a direct substitution we get 0 /0 so apply l'hopital's rule

  2. welshfella
    • one year ago
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    giving 2 sec^2 2t / 3

  3. elleblythe
    • one year ago
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    @welshfella Oh got it, okay thanks!

  4. welshfella
    • one year ago
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    - that isnt the answer thats just the result of differentiating the top and bottom of the function.

  5. welshfella
    • one year ago
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    if we now substitute directly we have 2 * (1) / 3 = 2/3 required limit is 2/3

  6. welshfella
    • one year ago
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    - perhaps you've worked that out already

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