elleblythe
  • elleblythe
How do we solve for this: lim(t->0) (tan2t)/3t
Mathematics
jamiebookeater
  • jamiebookeater
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welshfella
  • welshfella
if we do a direct substitution we get 0 /0 so apply l'hopital's rule
welshfella
  • welshfella
giving 2 sec^2 2t / 3
elleblythe
  • elleblythe
@welshfella Oh got it, okay thanks!

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welshfella
  • welshfella
- that isnt the answer thats just the result of differentiating the top and bottom of the function.
welshfella
  • welshfella
if we now substitute directly we have 2 * (1) / 3 = 2/3 required limit is 2/3
welshfella
  • welshfella
- perhaps you've worked that out already

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