anonymous
  • anonymous
IS ANYOME GOOD AT FINDING DERIATIVES FOR LN?! Please I need help as soon as possible! :(
Calculus1
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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alekos
  • alekos
post it up
anonymous
  • anonymous
Ok
anonymous
  • anonymous
y=ln(1-x/(x+2)^5)

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alekos
  • alekos
\[y=\ln [1 -\frac{ x }{(x+2)^{5}}]\] Is that it?
anonymous
  • anonymous
No sorry my computer is messed up, the 1-x is the numerator, and the denominator is as you out it. Ln is correct too
anonymous
  • anonymous
Put*
anonymous
  • anonymous
@alekos
IrishBoy123
  • IrishBoy123
\(\large y=ln \frac{1-x}{(x+2)^5} \) assuming that you know that \(\large (log \ u(x))' = \frac{1}{u} u'\) then look also at \(\large ln \frac{a}{b} = ln \ a - ln \ b\) and similar properties of logs; and maybe split this up a bit before you start...
alekos
  • alekos
yeah, thanks Irish Boy. I reckon do the properties of logs.... Ln(1-x) - Ln(x+2)^5 = Ln(1-x) - 5Ln(x+2) the rest is easy because the derivative of Lnx is 1/x
IrishBoy123
  • IrishBoy123
@alekos look good

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