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For the first equation, my solution is: y=(1,-1) y=(0,-3)
For the second one, my solution is: y= (1,1/2) y=(0,-3/2)
What am I doing wrong? Unless I'm misunderstanding how to graph. If that's the case then I'm ready to give up my own brains and use someone elses:)
Hey.. You will get one solution for both the equations?
It's supposed to be no solution my teacher said.
I'm actually about to blow up and die instead of waiting:)!
From first equation, bring x and y on one side and similarly do that in second equation, bring constant on right side..
Does that mean I solved it wrong?
The solution to a system is the points where all the curves meet Look at the graphs, do they seem to meet anywhere ?
2x - y = 3 4x - 2y = 3
I think your teacher is wrong then. :)
No, they don't so it's not solution.
Yeah I mean your teacher is right and you are not.. :P
Exactly! (1,-1) is a solution to first equation (1,1/2) is a solution to second equation but there is no solution to the system : from the graph it is clear that the lines are running parallel, so they not gonna intersect
So I guess the problem is that I'm graphing wrong then.....
which tool are you using to graph ?
What do you mean?
Thanks soo much!! Honestly I feel stupid everytime I ask you a question. Hahha!
This is a trick question, one easy way to know that the system has no solution is by working the slope of both the lines. If the slopes are equal and the equations are not same, then the lines are parallel and never intersect
Yeah, I've been trying to work these out and so far it's not coming along great how I wanted it too. But, I never heard that trick before. Thanks again!! You're a great help!!
Wait, I have another one similar to this one.
I actually have a question. For example when solving for an equation and one the question it says "any x-value can be used...." does that mean I can use any number and come out to the correct answer?