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YanaSidlinskiy
 one year ago
Solving by the graphing method!
Solve the system of equations by graphing.
2x=y+3
4x3=2y
YanaSidlinskiy
 one year ago
Solving by the graphing method! Solve the system of equations by graphing. 2x=y+3 4x3=2y

This Question is Closed

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.1For the first equation, my solution is: y=(1,1) y=(0,3)

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.1For the second one, my solution is: y= (1,1/2) y=(0,3/2)

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.1What am I doing wrong? Unless I'm misunderstanding how to graph. If that's the case then I'm ready to give up my own brains and use someone elses:)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Hey.. You will get one solution for both the equations?

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.1It's supposed to be no solution my teacher said.

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.1I'm actually about to blow up and die instead of waiting:)!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0From first equation, bring x and y on one side and similarly do that in second equation, bring constant on right side..

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2dw:1437585504562:dw

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.1Does that mean I solved it wrong?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2The solution to a system is the points where all the curves meet Look at the graphs, do they seem to meet anywhere ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.02x  y = 3 4x  2y = 3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think your teacher is wrong then. :)

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.1No, they don't so it's not solution.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yeah I mean your teacher is right and you are not.. :P

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2Exactly! (1,1) is a solution to first equation (1,1/2) is a solution to second equation but there is no solution to the system : from the graph it is clear that the lines are running parallel, so they not gonna intersect

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.1So I guess the problem is that I'm graphing wrong then.....

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2dw:1437586073316:dw

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2which tool are you using to graph ?

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.1What do you mean?

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.1Thanks soo much!! Honestly I feel stupid everytime I ask you a question. Hahha!

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2This is a trick question, one easy way to know that the system has no solution is by working the slope of both the lines. If the slopes are equal and the equations are not same, then the lines are parallel and never intersect

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.1Yeah, I've been trying to work these out and so far it's not coming along great how I wanted it too. But, I never heard that trick before. Thanks again!! You're a great help!!

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.1Wait, I have another one similar to this one.

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.1I actually have a question. For example when solving for an equation and one the question it says "any xvalue can be used...." does that mean I can use any number and come out to the correct answer?
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