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YanaSidlinskiy

  • one year ago

Solving by the graphing method! Solve the system of equations by graphing. 2x=y+3 4x-3=2y

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  1. YanaSidlinskiy
    • one year ago
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    For the first equation, my solution is: y=(1,-1) y=(0,-3)

  2. YanaSidlinskiy
    • one year ago
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    For the second one, my solution is: y= (1,1/2) y=(0,-3/2)

  3. YanaSidlinskiy
    • one year ago
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    What am I doing wrong? Unless I'm misunderstanding how to graph. If that's the case then I'm ready to give up my own brains and use someone elses:)

  4. anonymous
    • one year ago
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    Hey.. You will get one solution for both the equations?

  5. YanaSidlinskiy
    • one year ago
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    It's supposed to be no solution my teacher said.

  6. anonymous
    • one year ago
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    Wait..

  7. YanaSidlinskiy
    • one year ago
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    I'm actually about to blow up and die instead of waiting:)!

  8. anonymous
    • one year ago
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    From first equation, bring x and y on one side and similarly do that in second equation, bring constant on right side..

  9. ganeshie8
    • one year ago
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    |dw:1437585504562:dw|

  10. YanaSidlinskiy
    • one year ago
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    Does that mean I solved it wrong?

  11. ganeshie8
    • one year ago
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    The solution to a system is the points where all the curves meet Look at the graphs, do they seem to meet anywhere ?

  12. anonymous
    • one year ago
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    2x - y = 3 4x - 2y = 3

  13. anonymous
    • one year ago
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    I think your teacher is wrong then. :)

  14. YanaSidlinskiy
    • one year ago
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    No, they don't so it's not solution.

  15. YanaSidlinskiy
    • one year ago
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    *no solution

  16. anonymous
    • one year ago
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    Yeah I mean your teacher is right and you are not.. :P

  17. ganeshie8
    • one year ago
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    Exactly! (1,-1) is a solution to first equation (1,1/2) is a solution to second equation but there is no solution to the system : from the graph it is clear that the lines are running parallel, so they not gonna intersect

  18. YanaSidlinskiy
    • one year ago
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    So I guess the problem is that I'm graphing wrong then.....

  19. ganeshie8
    • one year ago
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    |dw:1437586073316:dw|

  20. ganeshie8
    • one year ago
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    which tool are you using to graph ?

  21. YanaSidlinskiy
    • one year ago
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    What do you mean?

  22. ganeshie8
    • one year ago
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    https://www.desmos.com/calculator

  23. YanaSidlinskiy
    • one year ago
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    Thanks soo much!! Honestly I feel stupid everytime I ask you a question. Hahha!

  24. ganeshie8
    • one year ago
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    This is a trick question, one easy way to know that the system has no solution is by working the slope of both the lines. If the slopes are equal and the equations are not same, then the lines are parallel and never intersect

  25. YanaSidlinskiy
    • one year ago
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    Yeah, I've been trying to work these out and so far it's not coming along great how I wanted it too. But, I never heard that trick before. Thanks again!! You're a great help!!

  26. YanaSidlinskiy
    • one year ago
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    Wait, I have another one similar to this one.

  27. YanaSidlinskiy
    • one year ago
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    I actually have a question. For example when solving for an equation and one the question it says "any x-value can be used...." does that mean I can use any number and come out to the correct answer?

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